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lisov135 [29]
3 years ago
13

Arlene sells computers and tablets, She earns an

Mathematics
1 answer:
maria [59]3 years ago
6 0

Answer:

Sorry i dont know the answer

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Find the value of (x + 1) in this equation.<br><br> 13(6x − 5) − x = 13 − 2(x + 1)
Mandarinka [93]

Answer: The value of x is 155/79.

Step-by-step explanation:

13(6x -5 )-x= 13 -2(x +1)

78x - 65- x = 13 -2x -2

77x -65 = 11-2x  

79x -65 =11

79x =76

x = 76/79    76/ 79 + 1/1  = 155/79

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3 years ago
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Sladkaya [172]

Answer:

The equation the 16 x 6 = 96

and she would have 6 bags of dog treats

Step-by-step explanation:

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3 years ago
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Vesnalui [34]

Answer:

AB = 25

Step-by-step explanation:

First things first, we know that these triangles are similar. Now let's find BC using the Pythagorean Theorem. BC = 5\sqrt5, this side is similar to the 5 side of the smaller triangle. That means each side of the larger triangle \sqrt5 times larger than the corresponding side on the small triangle. That means AB is \sqrt5 times larger than BC as well. So multiply BC by \sqrt5 get us the answer.

6 0
2 years ago
Evaluate y = 9 * (5/2)^x for x = -3.
dem82 [27]
You can find your answer by just substituting -3 for x......
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3 years ago
????⃗ (x,y)=(3x−4y)????⃗ +2x????⃗ F→(x,y)=(3x−4y)i→+2xj→ and ????C is the counter-clockwise oriented sector of a circle centered
Karolina [17]

By Green's theorem, the integral of \vec F along C is

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(2x)}{\partial x}-\frac{\partial(3x-4y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=6\iint_D\mathrm dx\,\mathrm dy

which is 6 times the area of D, the region with C as its boundary.

We can compute the integral by converting to polar coordinates, or simply recalling the formula for a circular sector from geometry: Given a sector with central angle \theta and radius r, the area A of the sector is proportional to the circle's overall area according to

\dfrac A{\frac\pi3\,\rm rad}=\dfrac{16\pi}{2\pi\,\rm rad}\implies A=\dfrac{8\pi}3

so that the value of the integral is

\dfrac{6\times8\pi}3=\boxed{16\pi}

6 0
3 years ago
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