The aquarium has 3 more yellow fish than green fish.
60% of the fish are yellow.
To find:
How many green fish are in the aquarium?
Step-by-step explanation:
Let there be x number of fish in the aquarium.
60% of the fish are yellow.
So there are 60x/100 = 3x/5 yellow fish.
Then (100 - 60)% = 40% fish are green.
So there are 40x/100 = 2x/5 green fish.
Given that, there are 3 more yellow fish than green fish
⇒ 3x/5 = 2x/5 + 3
⇒ 3x/5 = (2x + 15)/5
⇒ 3x = 2x + 15
⇒ 3x - 2x = 15
⇒ x = 15
Now, 2x/5 = 2/5 × 15 = 2 × 4 = 6
Answer:
There are 6 green fish in the aquarium.
Answer:
$125.25
Step-by-step explanation:
8.75*h+11.25*e
h is hours regular pay and e is extra pay for overtime. Since its an extra $2.50 for overtime, add that to the regular pay. Put in the hours:
Simplify by multiplying 8.75 by 8
Simplify by multiplying 11.25 by 5
Add
Since it says how much did each earn, as in individually, leave it as it is (unless regular pay was $2.18 an hour, which would be a rip-off). I'm pretty sure including the number of employees was meant to throw you off.
Answer:
I'm pretty sure its -4-12x but I could be wrong
Step-by-step explanation:
First I tried to solve for x but got -12x+4 so to get 4 on the other side of the equation I subtracted and got -4-12x I hope this helps :)
Answer: I think the last one sorry of I am wrong
Step-by-step explanation:
Answer:
a) 29.23% probability that a randomly selected home run was hit to right field
b) 29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes. It is said to be unusual if it is lower than 5% or higher than 95%.
(a) What is the probability that a randomly selected home run was hit to right field?
Desired outcomes:
19 home runs hit to right field
Total outcomes:
65 home runs
19/65 = 0.2923
29.23% probability that a randomly selected home run was hit to right field
(b) Was it unusual for this player to hit a home run to right field?
29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.
