Answer:
You can use either of the following to find "a":
- Pythagorean theorem
- Law of Cosines
Step-by-step explanation:
It looks like you have an isosceles trapezoid with one base 12.6 ft and a height of 15 ft.
I find it reasonably convenient to find the length of x using the sine of the 70° angle:
x = (15 ft)/sin(70°)
x ≈ 15.96 ft
That is not what you asked, but this value is sufficiently different from what is marked on your diagram, that I thought it might be helpful.
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Consider the diagram below. The relation between DE and AE can be written as ...
DE/AE = tan(70°)
AE = DE/tan(70°) = DE·tan(20°)
AE = 15·tan(20°) ≈ 5.459554
Then the length EC is ...
EC = AC - AE
EC = 6.3 - DE·tan(20°) ≈ 0.840446
Now, we can find DC using the Pythagorean theorem:
DC² = DE² + EC²
DC = √(15² +0.840446²) ≈ 15.023527
a ≈ 15.02 ft
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You can also make use of the Law of Cosines and the lengths x=AD and AC to find "a". (Do not round intermediate values from calculations.)
DC² = AD² + AC² - 2·AD·AC·cos(A)
a² = x² +6.3² -2·6.3x·cos(70°) ≈ 225.70635
a = √225.70635 ≈ 15.0235 . . . feet
Answer:

Step-by-step explanation:
Given the system of equations:


In order to find the y coordinate of the solution we must first find the solution to this system of equations. We first start by solving one of the given equations and then substitute the answer of that into the second equation and further solve to get the final answers.




















Hope this helps.
Answer:
-6,-9,-20,-25.
Step-by-step explanation:
You need to multiply a negative to make it positive as a negative multiplied by a negative equals a positive. But anything besides -1,-2,-3,-4,-5 and all positves can be placed.
If you would like to know how many total hours did Jeff work today, you can calculate this using the following steps:
4 2/3 hours in the morning + 3 3/4 hours in the afternoon = 4 2/3 + 3 3/4 = 14/3 + 15/4 = 56/12 + 45/12 = (56 + 45) / 12 = 101/12 = 8 5/12 hours
Jeff worked 8 5/12 hours in total.
48 on call = 3.5 hours for 10 dollars = 1/2 hours for 1.5