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densk [106]
3 years ago
15

A baseball player hit 65 home runs in a season. Of the 65 home​ runs, 19 went to right​ field, 23 went to right-center​ field, 9

went to center​ field, 11 went to left-center​ field, and 3 went to left field.
(a) What is the probability that a randomly selected home run was hit to right field?
(b) Was it unusual for this player to hit a home run to right field?
Mathematics
1 answer:
olchik [2.2K]3 years ago
8 0

Answer:

a) 29.23% probability that a randomly selected home run was hit to right field

b) 29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes. It is said to be unusual if it is lower than 5% or higher than 95%.

(a) What is the probability that a randomly selected home run was hit to right field?

Desired outcomes:

19 home runs hit to right field

Total outcomes:

65 home runs

19/65 = 0.2923

29.23% probability that a randomly selected home run was hit to right field

(b) Was it unusual for this player to hit a home run to right field?

29.23% probability that a randomly selected home run was hit to right field, which is not lower than 5% nor it is higher than 95%. So it was not unusual for this player to hit a home run to right field.

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What is the probability that a randomly selected contestant won a prize, given that the contestant was female write the probabil
pantera1 [17]

We have given the table of number of male and female contestants who did and did not win prize

The probability that a randomly selected contestant won prize given that contestant was female is

P(contestant won prize / Contestant was female)

Here we will use conditional probability formula

P(A/B) = \frac{P( A and B)}{P(B)}

Let Event A = selected contestant won prize and

event B = selected contestant is famale

Then numerator entity will

P(A and B) = P(Contestant won prize and Contestant is female)

= Number of female contestant who won prize / Total number of contestant

= 3 /(4+9+3+10)

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P(A and B) = 0.1153

P(B) = P(contestant is female )

= Number of female contestant / Total number of contestants

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P(B) = 0.5

Now P(A / B) = \frac{P( A and B)}{P(B)}

= 0.1153 / 0.5

P(A / B) = 0.2306

The probability that randomly selected contestant won prize given that contestant is female is 0.2306

Converting probability into percentage 23.06%

The percentage that randomly selected contestant won prize given that contestant is female is 23%

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Answer:

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Step-by-step explanation:

8

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3 0
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The expression that represents the ratio of the difference of the two means to Sidney’s mean absolute deviation is given by: Option B: 4/3.28

<h3>What is mean absolute deviation?</h3>

Mean absolute deviation is the average of the absolute deviation of each observation from their mean, for a considered set of observations.

For this case, the table of mean and mean absolute deviation is given as:

\begin{array}{ccc}&Mean&M.A.D.\\\text{Sidney}&82&3.28\\\text{Phill}&78&3.96\end{array}

(M.A.D refers to Mean Absolute Deviation).

So, difference in their mean is 82 - 78 = 4

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Learn more about ratio here:

brainly.com/question/12106245

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