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3 years ago

Which expression is equal to five over radical 11

Mathematics

1 answer:

Anarel [89]3 years ago

3 0

The solution to this is 5√(11)/11

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Anna11 [10]

Answer:I like the view

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2 years ago

The data shown are hourly wages of some employees of a small company. $5, $7, $8, $10, $24, $40 Which values, if any, are outlie

igor_vitrenko [27]

correct answer is "NONE" NOT $40. hOPE THIS HELPS!

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3 years ago

Find the area of the isosceles triangle.

kogti [31]

Answer:

The hight length : h

The base length : a

Apply the Pythagorean theorem in the right triangle :

h² = 13² - (10/2) = 144

h = √144 = 12 cm

S = (a x h)/ 2 = ( 10 x 12 )/2 = 60 cm²

Step-by-step explanation:

5 0

2 years ago

Which are the roots of the quadratic function f(b) = 62 – 75? Select two options.

elena55 [62]

Answer:

$b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}$

Step-by-step explanation:

Given

$f(b) = b^2 - 75$

Required

Determine the roots

To get the root of the function, then f(b) must be 0;

i.e. f(b) = 0

So, the expression becomes

$0 = b^2 - 75$

Add 75 to both sides

$75 + 0 = b^2 - 75 + 75$

$75 = b^2$

Take square roots of both sides

$\sqrt{75} = \sqrt{b^2}$

$\sqrt{75} = b$

Reorder

$b = \sqrt{75}$

Expand 75 as a product of 25 and 3

$b = \sqrt{25*3}$

Split the expression

$b = \sqrt{25} *\sqrt{3}$

$b = \±5 *\sqrt{3}$

$b = \±5 \sqrt{3}$

$b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}$

The options are not clear enough; however the roots of the equation are $b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}$

4 0

3 years ago

What is the seventh term of a geometric sequence that has a common ratio of –3 and the first term is –4?

rjkz [21]

An= A1 r ^(n-1)
An= -4 (-3)^(n-1)
An= -4 (-3)^(7-1)
An= -4 (729)
An= -2916

I think this is right :)

4 0

2 years ago