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What do I do and how do I do it

Ahat [919]

Show us the options so we can help

3 0

3 years ago

What is 12500 written in scientific notation?

swat32

Answer:The purpose of scientific notation is for scientists to write very large, or very small, numbers with ease.

Calculating scientific notation for a positive integer is simple, as it always follows this notation:

a x 10b

Follow the steps below to see how 12,500 is written in scientific notation.

Step 1

To find a, take the number and move a decimal place to the right one position.

Original Number: 12,500

New Number: 1.2500

Step 2

Now, to find b, count how many places to the right of the decimal.

New Number: 1 . 2 5 0 0

Decimal Count: 1 2 3 4

There are 4 places to the right of the decimal place.

Step 3

Building upon what we know above, we can now reconstruct the number into scientific notation.

Remember, the notation is: a x 10b

a = 1.25 (Please notice any zeroes on the end have been removed)

b = 4

Now the whole thing:

1.25 x 104

Step 4

Check your work:

104 = 10,000 x 1.25 = 12,500

Step-by-step explanation:

3 0

3 years ago

Plz, help. What is the mode?

Ronch [10]

Answer:

None

Step-by-step explanation:

Mode is the number that repeats the most. All of these numbers are unique, and there is no repeats, therefore there is no mode.

5 0

3 years ago

Read 2 more answers

PLEASE HELP NO LINKS

Artyom0805 [142]

Answer:

y = -2/3x + 3

Step-by-step explanation:

( -3, 5)

Parallel slope = -2/3

Slope-intercept:

y - y1 = m(x - x1)

y - 5 = -2/3(x + 3)

y - 5 = -2/3x - 2

y = -2/3x + 3

7 0

3 years ago

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

so

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

so

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0

3 years ago