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igor_vitrenko [27]
3 years ago
11

What is the opposite of six times the square of a number?

Mathematics
1 answer:
Ghella [55]3 years ago
5 0
I'm gonna break the problem down here.

The opposite of 6 times a number would be 6 divided by a number, agreed? Cool.

Then the opposite of the square of a number would be the square root of a number.

So just combine those: 6 divided by the square root of a number
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Stells [14]

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Answer:

  181

Step-by-step explanation:

The tagged deer seem to represent about 17/110 of the population. Since there are 28 deer with tags, the population (p) is estimated to be ...

  110/17 = p/28

  p = 28(110/17) ≈ 181

There are about 181 deer in the woods.

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3 years ago
Karita had $138.72 in her checking account . She wrote checks for $45.23 and $18.00. Then she made a deposit of 75.85 into her a
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What is the slope of the line y - 5 = -4(x - 8)?
galben [10]

Answer:

-4

Step-by-step explanation:

This looks like point-slope form, which I find personally hideous. Let's change it to slope-intercept form to ease my conscience. (remember that slope-intercept form is y=mx+b, where m=slope and b=y-intercept!)

y - 5 = -4(x-8)

y - 5 = -4x + 32

y = -4x + 37

It's in slope-intercept form now! And -4 looks to be our m.

<u>So the slope is -4.</u>

4 0
3 years ago
Read 2 more answers
Order from least to greatest 3.2 ,3.14, 19/7, sqrt (14)
Oksanka [162]

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7 0
3 years ago
Solve the system of linear equations.
sweet-ann [11.9K]

Answer:

  • dependent system
  • x = 2 -a
  • y = 1 +a
  • z = a

Step-by-step explanation:

Let's solve this by eliminating z, then we'll go from there.

Add 6 times the second equation to the first.

  (3x -3y +6z) +6(x +2y -z) = (3) +6(4)

  9x +9y = 27 . . . simplify

  x + y = 3 . . . . . . divide by 9 [eq4]

Add 13 times the second equation to the third.

  (5x -8y +13z) +13(x +2y -z) = (2) +13(4)

  18x +18y = 54

  x + y = 3 . . . . . . divide by 18 [eq5]

Equations [eq4] and [eq5] are identical. This tells us the system is dependent, and has an infinite number of solutions. We can find them in terms of z:

  y = 3 -x . . . . solve eq5 for y

  x +2(3 -x) -z = 4 . . . . substitute into the second equation

  -x +6 -z = 4

  x = 2 - z . . . . . . add x-4

  y = 3 -(2 -z)

  y = z +1

So far, we have written the solutions in terms of z. If we use the parameter "a", we can write the solutions as ...

  x = 2 -a

  y = 1 +a

  z = a

_____

<em>Check</em>

First equation:

  3(2-a) -3(a+1) +6a = 3

  6 -3a -3a -3 +6a = 3 . . . true

Second equation:

  (2-a) +2(a+1) -a = 4

  2 -a +2a +2 -a = 4 . . . true

Third equation:

  5(2-a) -8(a+1) +13a = 2

  10 -5a -8a -8 +13a = 2 . . . true

Our solution checks algebraically.

6 0
3 years ago
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