Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer: No slope
Step-by-step explanation: The line is going straight down.
It is rounded to the nearest tens. You can only round when you have 1,9. Hope I helped
To divide by a fraction, you multiply by its reciprocal, which you find by flipping the numerator and the denominator. 
Multiply the numerators and the denominators separately. 
Simplify by dividing both sides of the equation by 
. 
