Answer:
Depends how much is half a gallon in her car
usally a car has 100+ space for gallons
if she has any less than 50 gallons max
she won’t make it
so she probley will if she has more than 26 gallons of gas at half a tank
It would be 3.14(7)^2
Then 3.14*49
Multiply those two to get your area
Answer:
The answer is (-2)
Step-by-step explanation:
<h3><u>Given</u>;</h3>
- a₁ = (-6)
- a₂ = (-4)
- and so on,
<h3><u>To</u><u> </u><u>Find</u>;</h3>
Here, we will use AP
Now, Common Difference (d)
d = a₂ – a₁ = (-4) – (-6) = (-4) + 6 = 2
Here, Common Difference (d) is 2
So,
a₃ = a₂ + d
a₃ = (-4) + 2
a₃ = -2
Thus, The missing number in this sequence is (-2).
<u>-TheUnknownScientist 72</u>
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
Answer:
where is the question?
Step-by-step explanation: