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photoshop1234 [79]
3 years ago
15

Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 14 feet a

nd a height of 10 feet. Container B has a diameter of 10 feet and a height of 19 feet. Container A is full of water and the water is pumped into Container B until Conainter B is completely full. After the pumping is complete, what is the volume of the empty space inside Container A, to the nearest tenth of a cubic foot?
Mathematics
1 answer:
boyakko [2]3 years ago
4 0

Answer:

Volume of Cylinder A is                          pi times the area of the base times the height

                                                             π r2 h = (3.1416)(4)(4)(15) = 753.98 ft3

Volume of Cylinder B is likewise             pi times the area of the base times the height

                                                             π r2 h = (3.1416)(6)(6)(7)   = 791.68 ft3

After pumping all of Cyl A into Cyl B

there will remain empty space in B         791.68 – 753.98 = 37.7 ft3  

The percentage this empty space is

of the entire volume is                            37.7 / 791.68 = 0.0476 which is 4.8% when rounded to the nearest tenth  

.

Guest Apr 26, 2020

Step-by-step explanation:

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Answer:

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kirill115 [55]

Answer:

slope m = 0

Step-by-step explanation:

To find the slope for two points, you need use

m = (y2 - y1)/(x2-x1)

for point 1 (-1, -4) and point 2 (-2, -4)

m = (-4 - (-4)) / ((-2)-(-1))

m = 0 / -1

when the top number is zero, the answer is 0

if you plot the points in a graph, it is a horizontal line or y = mx + b = 0m -4

y = -4

7 0
3 years ago
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He pressure of a tyre is 32 pounds per square inch. Given 1 pound = 0.4536 kilograms 1 inch = 2.54 centimetres Work out the pres
ss7ja [257]

Step-by-step explanation:

1pound =0.4536kiligrams=,453.6grams

1square inch =2.54×2.54=6.4516

(32pounds/inch√2square

×453.6g)

(14515.2g/inch √2

÷6.4516)/6.4516

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7 0
2 years ago
Write the equation of the given line in slope-intercept form
Snowcat [4.5K]

Answer:

y = -3x -1

Step-by-step explanation:

Hi there!

We are given a line on a coordinate grid, with 2 marked points, (-1, 2) and (1, -4)

We can use these points to help find the equation of the line, which we can write in slope-intercept form

Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept

First, we need to find the slope of the line
The formula for the slope calculated from 2 points is \frac{y_2-y_1}{x_2-x_1}, where (x_1, y_1) and (x_2, y_2) are points

We have everything we need to find the slope, but let's label the values of the points to help avoid confusion.

x_1=-1\\y_1=2\\x_2=1\\y_2=-4

Now substitute these values into the formula to find the slope

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{-4-2}{1--1}

Simplify

m=\frac{-4-2}{1+1}

m=\frac{-6}{2}

Divide

m= -3

The slope of the line is -3

We can substitute this into the formula.
Here's our line so far:

y = -3x + b

Now we need to find b

As the equation passes through the points (-1, 2) and (1, -4), we can use either one to find the value of b

Taking (-1, 2) for example:

Substitute -1 as x and 2 as y.

2 = -3(-1) + b

multiply

2 = 3 + b

Subtract 3 from both sides

-1 = b

Substitute -1 as b.

y = -3x - 1

Hope this helps!

See more on this topic here: brainly.com/question/27402935

8 0
2 years ago
Performance task trigonometric identities
marishachu [46]

#1

\\ \sf\longmapsto cos75°

\\ \sf\longmapsto cos(45+30)°

\\ \sf\longmapsto cos45cos30+sin45.sin30

\\ \sf\longmapsto \dfrac{1}{\sqrt{2}}\times \dfrac{\sqrt{3}}{2}+\dfrac{1}{\sqrt{2}}\times \dfrac{1}{2}

\\ \sf\longmapsto \dfrac{\sqrt{3}}{2\sqrt{2}}+\dfrac{1}{2\sqrt{2}}

\\ \sf\longmapsto \dfrac{\sqrt{3}+1}{2\sqrt{2}}

#2

\\ \sf\longmapsto tan\left(-\dfrac{\pi}{12}\right)

\\ \sf\longmapsto tan(-15°)

\\ \sf\longmapsto \dfrac{sin(-15)}{cos(-15)}

\\ \sf\longmapsto \dfrac{-sin15}{cos15}

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\\ \sf\longmapsto -\left(\dfrac{\sqrt{3}-1}{\sqrt{3}+1}\right)

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3 years ago
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