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3 years ago

Don't know how to solve please help

Mathematics

2 answers:

lesantik [10]3 years ago

4 0

50+ <DGE+2X=180

<DGE+2X=130

2X=100

X=50

Mnenie [13.5K]3 years ago

3 0

3. acute, 30° c
I don't really know the next bit though. I thought I had it but then I read it. it is east but it is early in the morning for me

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$1,200, 3.9, 8 months

Kryger [21]

Are you working with simple interest?

3 0

3 years ago

Solve the system using elimination. ''x-3y=9 and -x+3y=-9

DiKsa [7]

Answer:

Infinitely many solutions.

Step-by-step explanation:

Let's solve your system by elimination.

x−3y=9;−x+3y=−9

x−3y=9

−x+3y=−9

Add these equations to eliminate x:

0=0

Answer:

Infinitely many solutions.

6 0

2 years ago

I need help please help

Rufina [12.5K]

A. pat x-10 is a negative

6 0

3 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

Solve the system by substitution. y = 8x y=10x – 4 Submit Answer How

Goshia [24]

Answer:

(2,16)

Step-by-step explanation:

y=8x-----------(i)

y= 10x-4---------(ii)

Substituting the value of y=8x in equation (ii)

8x=10x-4

8x-10x=-4

-2x= -4

x=2

Now, substituting the value of x= 2 in equation (i)

y=8x=8(2)=16

Solution of the system is (2,16)

6 0

3 years ago