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2 years ago

Actorize Completely PQ+ PR - RQ -Q²

Mathematics

1 answer:

sp2606 [1]2 years ago

8 0

Answer:

(Q + R)(P - Q)

Step-by-step explanation:

PQ + PR - RQ - Q² = (Q + R)(P - Q)

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A change in velocity a. speed b. velocity c. acceleration

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Answer:

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3 years ago

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Which equation is correct?

olga2289 [7]

Equation which is correct

792 × 5 = 700 × 5 + 90 × 5 + 2 × 5

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2 years ago

The radius of a circle is 13 find its area un terms of pi

Leto [7]

The area of the circle is given as:

$A=\pi r^2$

Plugging the value of the radius we have that:

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Therefore the area in terms of pi is:

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1 year ago

A) Write 600 as the product of prime factors. Give your answer in index form.

dlinn [17]

Answer:

3 × 5 × 5 × 2 × 2 × 2

Step-by-step explanation:

Make a factor tree.

But let me explain the above to prove it's correct.

3 × 5 = 15

15 × 5 = 75

75 × 2 = 150

150 × 2 = 300

300 × 2 = 600

Therefore 600 as a product of prime factors is: 3 × 5 × 5 × 2 × 2 × 2

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3 years ago

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What are the solutions to the quadratic equation below x^2+20x+100=7

aleksandrvk [35]

First you must have the quadratic equal to zero. In order to do this you must subtract 7 to both sides

x^2 + 20x + (100 - 7) = 7 - 7

x^2 + 20x + 93 = 0

Now you must find two numbers who's sum equals 20 and their multiplication equal 93

Are there any? NO!

This means that you have to use the formula:

$\frac{-b±\sqrt{b^{2} - 4ac} }{2a}$

In this case:

a = 1

b = 20

c = 93

$\frac{-(20) plus/minus\sqrt{20^{2} - 4(1)(93)} }{2*1}$

$\frac{-20 plus/minus\sqrt{400 - 372} }{2}$

$\frac{-20 plus/minus\sqrt{28} }{2}$

^^^We must simplify √28

√28 = 2√7

so...

$\frac{-20 plus/minus 2\sqrt{7} }{2}$

simplify further:

$-10 plus/minus\sqrt{7$

-10 + √7

-10 - √7

***plus/minus = ±

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0

3 years ago

Actorize Completely PQ+ PR - RQ -Q²​

Actorize Completely PQ+ PR - RQ -Q²