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harina [27]
3 years ago
5

I only need the answers to b and c, no work is needed thank you

Mathematics
2 answers:
Mashcka [7]3 years ago
7 0
Roots: 3 & -2
Factors: (x-3) & (x+2)
Quadratic Equation formed: (x+2)(x-3)= x^2-3x+2x-6= x^2-x-6
Luden [163]3 years ago
3 0

Answer:

So for the factors it will be 2,3 and the equation would be 1,3 to 2,3.

Step-by-step explanation:

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What is the volume of a cylinder, in cubic inches, with a height of 2 inches and a base diameter of 4 inches? Round to the neare
joja [24]

Answer:

the answer for the volume of the cylinder is V≈25.13in³

6 0
3 years ago
Recall that a 6-bit string is a bit strings of length 6, and a bit string of weight 3, say, is one with exactly three 1's. How m
strojnjashka [21]

Answer:

1.. Total number of 6 bit strings is 64

2. Number of 6-bit strings with weight of 0 is 1

3. Number of 6-bit strings with weight of 1 is 6

4. Number of 6-bit strings with weight of 3 is 20

5. Number of 6-bit strings with weight of 5 is 6

6. Number of 6-bit strings with weight of 6 is 1

7. Number of 6-bit strings with weight of 7 is 0

Step-by-step explanation:

A bit string is a string that contains 0 and 1 only

1. Total number of 6 bit strings is 2^6 = 64

2. Number of 6 bit strings with weight 0 is 1

Explanation

Weight 0 means a string with no occurrence of 1

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 0 i.e. no occurrence of 1

6C0 = 6!/(6-0)!0!

6C0 = 6!/6!0!

6C0 = 1

Hence, the number of string with weight 0 (i.e. no occurrence of 1 ) is 1

3. Number of string with weight 1 is 6

Explanation

Weight 0 means a string with exactly 1 occurrence of '1'

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 1

6C1 = 6!/(6-1)!1!

6C1 = 6!/5!1!

6C1 = 6

Hence, the number of string with weight 6

4. Number of string with weight 3 is 20

Explanation

n = 6 and r = 3

6C3 = 6!/(6-3)!3!

6C3 = 6!/3!3!

6C3 = 20

Hence, the number of string with weight 3 is 20

5. Number of string with weight 5 is 6

Explanation

n = 6 and r = 5

6C5 = 6!/(6-5)!5!

6C5 = 6!/1!5!

6C5 = 6

Hence, the number of string with weight 5 is 6

6. Number of string with weight 6 is 1

Explanation

n = 6 and r = 6

6C6 = 6!/(6-6)!6!

6C6 = 6!/0!6!

6C6 = 1

Hence, the number of string with weight 6 is 1

7. Number of string with weight 7 is 0

Weight of 7 means that a string that has 7 occurrence of 1

The total length of a 6 bit is 6

Since 6 is less than 7, there's no way a bit of weight 7 can occur.

So, the right answer for this is 0.

8 0
3 years ago
Trig help please!!! This is due tomorrow. If you don’t mind could you please explain how you do it
vivado [14]

Answer:

The larger acute angle is equal to 50.8 degrees.

Step-by-step explanation:

Let's solve for both of the acute angles for the purpose of checking our work at the end with angle A being the top angle and angle B being the one on the base of the triangle (that's not the 90 degrees one). Determining whether to use sin/cos/tan comes from SOH-CAH-TOA.

A = cos^-1 (2√6/2√15)

However, you need to move the radical out of the denominator by multiplying √15 to the numerator and denominator. You should come up with (2√90)/30. So,

A = cos^-1 (2√90/30) = 50.768 degrees.

B = sin^-1 (2√90/30) = 39.231 degrees.

Now, we can check the work by adding the 2 angles to 90 and, if it comes to 180, it's right.

cos^-1 (2√90/30) + sin^-1 (2√90/30) + 90 = 180.

If you have any questions on where I got a formula or any step, feel free to ask in the comments!

8 0
3 years ago
yesterday 50 bakery customers muffins and 11 of those customers bought bran muffins if 150 customers buy muffin's tomorrow how m
Andrews [41]

Answer:

33 banana muffins

Step-by-step explanation:

11/50 = x/150

50x=1650

50x/50=1650/50

x=33 !

8 0
2 years ago
The expression x^4 - 16 is equivalent to :
Zanzabum
The correct answer is b
8 0
3 years ago
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