Answer:
The brown-eyed parents must be HETEROZYGOUS to produce a blue-eyed child
Explanation:
This question involves a single gene coding for eye color in humans. The allele for brown eyes (B) are dominant over the allele for blue eyes (b). This means that an individual that is heterozygous (Bb) will phenotypically have a brown eyes.
According to this question, a blue-eyed child (bb) will be produced when two brown-eyed parents are HETEROZYGOUS (Bb) for the eye color trait. This means that each of the parent donated the recessive allele (b) to produce the (bb) offspring. Please find the punnet square attached.
Answer:
A) 300
B) 3:1
C) 9 long yellow : 3 long green : 3 short yellow : 1 short green
Explanation:
Long stems (L_) are dominant to short stems (ll)
Yellow seeds (Y_) are dominant to green seeds (yy)
We interbred pea plants with long stems and yellow seeds (L_Y_), but they had a short green parent (llyy) that could have only produced <em>ly</em> gametes, so our plants are heterozygous <em>LlYy</em>.
C) We interbred them LlYy x LlYy. If the two genes are unlinked, this is a typical dihybrid cross and from Mendel's law of independent assortment we know that the offspring will have the following phenotypic ratios:
- 9/16 L_Y_ (Long, yellow)
- 3/16 L_yy (Long, green)
- 3/16 llY_ (short, yellow)
- 1/16 llyy (short, green)
A) 3/16 × 1600 = 300 plants will be long and green.
B)
9/16 + 3/16 = 12/16= 3/4 plants will be yellow;
3/16 + 1/16 = 4/16= 1/4 plants will be green.
The ratio will be 3 yellow : 1 green
Answer:
C
Explanation:
water is combined to be essential in food processing (photosynthesis)
