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jenyasd209 [6]
3 years ago
11

Lucy collects data from a random sample of seventh-graders. Out of 40 respondents, 7 attend afterschool programs. Of the 200 sev

enth-graders attending Lucy’s school, how many would be expected to attend afterschool programs?
PLEASE HELP ASAP
WILL GIVE BRANLIEST :)
Mathematics
1 answer:
harkovskaia [24]3 years ago
7 0

Answer:

7

Step-by-step explanation:

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Please help, Easy maths.
svetoff [14.1K]

Answer:

x-5y

Step-by-step explanation:

6x-8y-5x+3y

Add or subtract like terms.

1x-5y

8 0
3 years ago
Read 2 more answers
Can someone help me with this?​
Mariulka [41]

Answer:

1) 4+5=9.

2)  2+(-6)=-4

3)  -3+(-7)=-10

4)  (-7)+3=-4

5)  9+(-4)=5

6)  -1+4=3

7)  5+(-5)=0

8)  -3+(-6)=-9

Step-by-step explanation:

In the given number lines, rightarrows represent positive integers and leftarrows represent negative integers.

1)

In first number line we have two rightarrows.

Rightarrow from 0-4 = 4

Rightarrow from 4-9 = 5

So, required sum is 4+5=9.

Similarly,

2)

2+(-6)=-4

3)

-3+(-7)=-10

4)

(-7)+3=-4

5)

9+(-4)=5

6)

-1+4=3

7)

5+(-5)=0

8)

-3+(-6)=-9

8 0
3 years ago
Several years​ ago, 38​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students r
Colt1911 [192]

Answer:

0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995

0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive

The confidence level is given 95%, the significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical values are:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The estimated proportion of people satisfied with the quality of education the students receive is given by:

\hat p =\frac{499}{1165}= 0.428

The confidence interval for the proportion if interest is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing the info given we got:

0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995

0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

8 0
4 years ago
I really need help someone
Ann [662]

with what english, science anything i no it all

8 0
3 years ago
Calcular el área y el perímetro de un círculo que tiene 50 cm de radio
gulaghasi [49]

Answer:

Area: 7850 square cm

Perimeter: 314 cm.

Step-by-step explanation:

The area is \pi r^{2}. With r=50, \pi 50^{2}=2500π which is about (2500)(3.14)=7850.

The perimeter is 2\pi r which is the same as (diameter)(π). The diameter is 100, so 100\pi which is about (100)(3.14)=314.

8 0
3 years ago
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