Ask question

Ask question

All categories

3 years ago

11

Lucy collects data from a random sample of seventh-graders. Out of 40 respondents, 7 attend afterschool programs. Of the 200 sev

enth-graders attending Lucy’s school, how many would be expected to attend afterschool programs?
PLEASE HELP ASAP
WILL GIVE BRANLIEST :)

1 answer:

harkovskaia [24]3 years ago

7 0

Answer:

7

Step-by-step explanation:

You might be interested in

I have 3 quarter , 1 nickel , 1 dime , and 3 penny . But I want to divided 2 people .

Andru [333]

The answer would be 93 cents divide it by 2 since you want to share with someone and you would have 46 cents and a nickel for both people

7 0

3 years ago

Read 2 more answers

How to do logarithmic equations

kaheart [24]

Answer:To solve a logarithmic equation, rewrite the equation in exponential form and solve for the variable. (it’s kind of the similar to regular equation)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi

inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

$\displaystyle\frac{dr}{dt} = -7\text{ inch per second}$

The volume is decreasing at a constant rate.

$\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}$

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

$V = \displaystyle\frac{1}{3}\pi r^2 h$

Instant volume =

$525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}$

Differentiating with respect to t,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)$

Putting all the values, we get,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131$

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0

3 years ago

Plz help ASAP I will mark u branliest

-BARSIC- [3]

Answer:

Brainliest?

Step-by-step explanation:

1.

subtract 1 from both sides

divide by 2

2.

add 5 to each side

divide by 4

6 0

3 years ago

Read 2 more answers

NEED HELP ASAPPP!!!!!!

abruzzese [7]

Answer:

B

Step-by-step explanation:

Square both sides, and get s^2 = k3/p

next multiply both sides by p and get (s^2)(p)=k3

Therefore k3 equals s^2 times p

6 0

2 years ago

Read 2 more answers