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Mars2501 [29]
3 years ago
6

How many g in 45 kg?

Mathematics
1 answer:
tigry1 [53]3 years ago
5 0
45000 grams
Hope this helps. Have a amazing day and stay safe <3
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Solve the system below using an appropriate method.
fiasKO [112]
Using substitution:
4x+2y=12
y=8x+1

4x+2(8x+1)=12

distribute
4x+16x+2=12

combine like terms
18x+2=12

subtract 2 from both sides
20x=10

divide each side by 20
x=10/20

reduce
x=1/2

plug in x for the y= equation
y=8(1/2)+1

multiply
y=4+1

add
y=5

answer:
(1/2,5)
5 0
2 years ago
an airplane is cruising at an altitude of 40000 feet begins at a distant to land it loses altitude at a rate of 1500 feet per mi
Lemur [1.5K]
27.7-. or is it something else?!?!?
7 0
3 years ago
Please help me ill put the question up for a lot of point, and i will mark as brainliest!!!
sattari [20]

Step-by-step explanation:

(2x³y^-4)^-2 = 1/(4x⁶y^‐8) = y⁸/(4x⁶)

1/(8x⁵y^-7) = y⁷/(8x⁵)

4x^-9y⁴ = 4y⁴/x⁹

so, the whole expression is then

y⁸/(4x⁶) × y⁷/(8x⁵) × 4y⁴/x⁹

4y¹⁹/(32x²⁰) = y¹⁹/(8x²⁰)

so, D is the correct answer.

6 0
2 years ago
One card is randomly selected from a deck of cards find the odds against drawing a seven
Stella [2.4K]

Answer:

\frac{3}{4}

Step-by-step explanation:

Probability of getting a 7 + Probability of not getting a 7 = 1.

Odds against drawing a 7 = Probability of not getting a 7.

We could calculate the probability of getting a 7 and subtract 1 from it to get the answer.

There a four sevens in a deck of card, one of each kind.

Probability of getting a 7 = $ P(7) = \frac{4}{52} = \frac{1}{13} $

$ \implies P(not \hspace{1mm} getting \hspace{1mm} a \hspace{1mm} 7) = 1 - P(7) $

$ \implies $ P(not getting a 7) $ = 1 - \frac{1}{13} = \frac{12}{13} $

4 0
3 years ago
Solve the equations PLEASEE<br><br> -1=3x-2<br><br> -3x=9<br><br> -10=-5x
Ilia_Sergeevich [38]

Answers are in bold:

-1=3x-2

add 2 to both sides

-1+2=3x-2+2

1=3x

divide both sides by 3

1÷3=3x÷3

1/3=x

-3x=9

divide both sides by -3

-3x÷-3=9÷-3

x=-3

-10=-5x

divide both sides by -5

-10÷-5=-5x÷-5

2=x

I hope this is good enough:

6 0
3 years ago
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