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2 years ago

Plsss hello me I’m going to get a whooping !!

Mathematics

2 answers:

tatuchka [14]2 years ago

8 0

Answer:

411, 467, 523

Step-by-step explanation:

add 56 to each cycle

411+56 = 467

467+56 = 523

mixer [17]2 years ago

3 0

Answer: 467, 523, 579

Step-by-step explanation:

You won’t get a whooping I promise :)

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Someone please helpp

umka2103 [35]

Answer:

The two equations are similar because they both end up with the same common value. 0=0 The work you need to show that this is correct will be shown below.

Step-by-step explanation:

2(5m−4)−3(m−5)2=−3m2+40m−83

Add 3m^2 to both sides.

−3m2+40m−83+3m2=−3m2+40m−83+3m2

40m−83=40m−83

Subtract 40m from both sides.

40m−83−40m=40m−83−40m

−83=−83

−83+83=−83+83

0=0

If you have any questions regarding my answer please tell me in the comments, I will come and answer them. Have a good day.

6 0

2 years ago

From a well shuffled deck of 52 cards, the probability of NOT drawings a red-face card is ______.

Gnom [1K]

Answer:

Option "d" might be 11/13

Step-by-step explanation:

Red face cards=8. ( heart and Diamond)

Remove this 8 cards from 52 cards which gives

=>44

Toal cards =52

PROBABILITY = 44/52=>11/13

5 0

2 years ago

At 3 p.m. an oil tanker traveling west in the ocean at 14 kilometers per hour passes the same spot as a luxury liner that arrive

schepotkina [342]

<span>N(t) = 16t ; Distance north of spot at time t for the liner. W(t) = 14(t-1); Distance west of spot at time t for the tanker. d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t. Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is N(t) = 16t Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is W(t) = 14(t-1) The distance between the 2 ships is easy. Just use the pythagorean theorem. So d(t) = sqrt(N(t)^2 + W(t)^2) If you want the function for d() to be expanded, just substitute the other functions, so d(t) = sqrt((16t)^2 + (14(t-1))^2) d(t) = sqrt(256t^2 + (14t-14)^2) d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) ) d(t) = sqrt(452t^2 - 392t + 196)</span>

3 0

3 years ago

Given the following system of equations: 2x + 6y = 12 4x + 3y = 15 Which action creates an equivalent system that will eliminate

Charra [1.4K]

Option A and B are correct.

Step-by-step explanation:

We are given the following systems of equation:

$2x + 6y = 12 \\4x + 3y = 15$

We need to identify the action creates an equivalent system that will eliminate one variable when they are combined.

Checking the options:

a) Multiply the second equation by −2 to get −8x − 6y = −30

If we add equation(1) and the new equation(2) the variable y will be eliminated. So, this is the correct option.

b) Multiply the first equation by 2 to get 4x + 12y = 24.

If we subtract new equation(1) and equation(2), the variable x will be eliminated. So, this is the correct option.

c) Multiply the second equation by −4 to get −16x − 12y = −60

By adding or subtracting, none of the variable is eliminated. So, it is not the correct option.

d) Multiply the first equation by −4 to get −8x − 24y = −48.

By adding or subtracting, none of the variable is eliminated. So, it is not the correct option.

So, Option A and B are correct.

Keywords: Solve System of equations

Learn more about solving system of equations at:

#learnwithBrainly

7 0

2 years ago

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Rearrange the equation so xxx is the independent variable. 6x+y=4x+11y6x+y=4x+11y

slava [35]

Answer:

10x=10y so x and y are the same or x=y

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers