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Luda [366]
2 years ago
11

Plsss hello me I’m going to get a whooping !!

Mathematics
2 answers:
tatuchka [14]2 years ago
8 0

Answer:

411, 467, 523

Step-by-step explanation:

add 56 to each cycle

411+56 = 467

467+56 = 523

mixer [17]2 years ago
3 0

Answer: 467, 523, 579

Step-by-step explanation:

You won’t get a whooping I promise :)

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A market research firm knows from historical data that telephone surveys have a 36% response rate. In a random sample of 280 tel
Rasek [7]

Answer:

0.6604

Step-by-step explanation:

Given that a market  research firm knows from historical data that telephone surveys have a 36% response rate.

Sample size of random sample = 280

We know for samples randomly drawn of large size sample proportion follows a normal distribution with mean= sample proportin and std error

= \sqrt{\frac{pq}{n} }

Substitute p = 0.36 and q = 1-0.36= 0.64

p follows N with mean = 0.36 and std dev = \sqrt{\frac{0.36*0.64}{\sqrt{280} } } \\=0.0287

Using normal distribution values we can find\

P(33.5p.c. < p < 39pc)\\= P(0.335

3 0
3 years ago
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What is the value of m so that the two expressions are equivalent?
Law Incorporation [45]

Answer: 0

Step-by-step explanation:

Since m is with x, you don't need to care about y

We would get 2x - 6x + 4x = mx

0x = mx

m is 0

8 0
2 years ago
Drag each tile to the correct box. Match the expression to the exponent property that you use first to simplify the expression
amid [387]
Do you have the tiles and stuff 

5 0
3 years ago
Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

  • \sin{\theta} < \cos{\theta} if 0^{\circ} < \theta;
  • \sin{\theta} > \cos{\theta} if 45^{\circ} < \theta;
  • \sin{\theta} = \cos{\theta} if \theta = 45^{\circ}.

4 0
3 years ago
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I need helpp hurry plzz!!!
wariber [46]

Answer:

B. 2x2

Step-by-step explanation:

5 0
2 years ago
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