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Veseljchak [2.6K]
3 years ago
15

Write an equation for this graph please help me I'm begging u

Mathematics
1 answer:
bekas [8.4K]3 years ago
4 0
First, solve for the slope. This can be found by looking at the y and x intercepts. At x = 0, y = 1.5. At x = 2, y = 0.

Slope is defined as Δy/Δx, or the change in y over the change in x. This means that in order to calculate the slope, you must find the difference between the values of y and divide it by the difference in the values of x for the two points to determine the slope between them.

(0 - 1.5)/(2-0) = (-1.5)/2 = -0.75 or -3/4

Now that you have the slope, we can write the equation in slope intercept form, y = mx + b, where m is the slope we calculated and b is the y intercept, 1.5.

y = (-3/4)x + 1.5
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Answer:

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Step-by-step explanation:

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The quadratic equation which matches given solution is x² + 3x + 3 = 0. Then the correct option is C.

<h3>What is a quadratic equation?</h3>

It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.

We know that the formula

\rm x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

The solutions are given below.

\rm x = \dfrac{-3 \pm \sqrt3 \iota }{2}

Then

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\rm x = \dfrac{-6\pm 6\iota}{4}\\\\x = \dfrac{-3\pm 3 \iota}{2}

2)  x² + 3x + 12 = 0, the zeroes of the equation will be

\rm x = \dfrac{-3\pm \sqrt{39}\iota}{2}

3)  x² + 3x + 3 = 0, the zeroes of the equation will be

\rm x = \dfrac{-3\pm \sqrt3\iota}{2}

4)  2x² + 6x + 3 = 0, the zeroes of the equation will be

\rm x = \dfrac{-6\pm 2\sqrt{3}}{4}\\\\x = \dfrac{-3\pm \sqrt3 }{2}

More about the quadratic equation link is given below.

brainly.com/question/2263981

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