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3 years ago

9

Which value for x makes the sentence true?

1 answer:

Nat2105 [25]3 years ago

3 0

<span>A. x = 2
Would make your statement true</span>

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A decorator has just painted 400 tiles blue and green at a ratio of 5:20.how many were painted green ? how many were painted blu

zheka24 [161]

Blue tiles are 80.
Green tiles are 320

8 0

3 years ago

That's the question ??

Oksanka [162]

Step-by-step explanation:

Before we answer, the area of a Circle given it radius is

$a = \pi r {}^{2}$

The area of a circle given it diameter is

$a = \pi( \frac{d}{2} ) {}^{2}$

So let answers question 1-4.

1. The area is

$1024\pi$

2. The area is

$576\pi$

3.

$1.225\pi$

4.

$309.76\pi$

For the 5th problem, circumference is

$\pi \times d$

where d is the diameter and

$2\pi r$

where r is the radius.

A circumference of 100 m means the radius is 50 because

$2\pi \times r = 100\pi$

$r = 50$

So this means the area is

$2500 {\pi}$

3 0

2 years ago

los trabajadores de una mina se encuentran a 20 metros bajo tierra .Si excavan 3 metros desde alli suben otros 8 metros para cog

Yakvenalex [24]

Step-by-step explanation:

la carretilla estaba a unos 15 metros de altura

8 0

2 years ago

This person did something wrong and I do not know what it is :( Please help this is for points!

Inga [223]

Answer:

It is, indeed, a reduction. But, the scale factor of the dilation should be a fraction instead of a whole number, since the shape has shrunk.

Instead of $\frac{KN}{K'N'}$ , it should be $\frac{K'N'}{KN}$ . That would make it (4 - 2) / (8 - 4) = 2 / 4 = 1/2.

Hope this helps!

7 0

3 years ago

Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i

shepuryov [24]

Answer:D) 1 hr

Step-by-step explanation:

Given

Pump A and B can fill tank in $\frac{6}{5} hr$

Pump A and C can fill tank in $\frac{3}{2} hr$

Pump B and C can fill tank in $2 hr$

Let A be the total hr taken A therefore rate of $A=\frac{1}{A} /hr$

Let B be the total hr taken B therefore rate of $B=\frac{1}{B} /hr$

Let C be the total hr taken C therefore rate of $C=\frac{1}{C} /hr$

$\frac{1}{A}+\frac{1}{B}=\frac{5}{6}$ -----1

$\frac{1}{B}+\frac{1}{C}=\frac{1}{2}$ -----2

$\frac{1}{A}+\frac{1}{C}=\frac{2}{3}$ -----3

Adding 1,2 & 3

$2(\frac{1}{A}+\frac{1}{B}+\frac{1}{C})=\frac{5}{6}+\frac{1}{2}+\frac{2}{3}$

$\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{2}{2}$

$\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1$

thus time taken by A,B and C combined is 1 hr

7 0

3 years ago