This is adding two vectors, one magnitude 300 direction east, and one magnitude 100 direction 30 degrees northeast.
For the resulting sum we can use the Law of Cosines or just add up the components. Let's try it both ways.
Components first. In the east direction we have
300 + 100 cos 30° = 300 + 100(√3/2) = 386.60 miles per hour
In the north direction we have
0 + 100 sin 30° = 100 (1/2) = 50 miles per hour
So a total speed of
sqrt{386.6^2 + 50^2} = 389.82 miles per hour
Answer: 389.82
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OK let's try the Law of Cosines. We have sides 300 and 100 and included angle 150°.
Go 2 openstudy hope that helped
Answer:
24
Step-by-step explanation:
so multiplies see och the rest of the world and the second half and the other hand if you have a good and the second one is the only way only a and the other is the first time I saw one he and only best o
Answer: x = 4 and y = -3
Step-by-step explanation:
2x + 4y = -4
2x = -4 - 4y
x = -2 - 2y
Now that we have solved the first equation for x, we plug (-2 - 2y) into the other equation in place of x and then solve for y.
3(-2 -2y) + 5y = -3
-6 - 6y + 5y = -3
-y = 3
y = -3
Now that we know y, we plug it into the original equation and solve for x.
2x + 4(-3) = -4
2x + -12 = -4
2x = 8
x = 4
You can check the answer by plugging both x and y into either of the original equations.
Answer: A) 126.6
<u>Step-by-step explanation:</u>
Since we know ∠B = 85° and ∠C = 53°, we can use the Triangle Sum Theorem (angles of a triangle = 180°) to calculate ∠A.
∠A + ∠B + ∠C = 180
∠A + 85 + 53 = 180
∠A + 138 = 180
∠A = 42
Now we have:
A = 42 B = 85 C = 53
a = 85 b = ??? c = ???
We have all of the information for ∠A and side a so we can use the Law of Sines to find b (AC).
