Answer:
(x)^2 (y)^2
---------- + --------- = 1
4 3
Step-by-step explanation:
The standard equation for an ellipse is
(x-h)^2 (y-k)^2
---------- + --------- = 1
a^2 b^2
The center is at (h,k)
The vertices are at (h±a, k)
The foci are at (h±c,k )
Where c is sqrt(a^2 - b^2)
It is centered at the origin so h,k are zero
(x)^2 (y)^2
---------- + --------- = 1
a^2 b^2
The center is at (0,0)
The vertices are at (0±a, 0)
The foci are at (0±c,0 )
The vertices are (±2,0) so a =2
The foci is 1
c = sqrt(a^2 - b^2)
1 = sqrt(2^2 - b^2)
Square each side
1 = 4-b^2
Subtract 4 from each side
1-4 = -b^2
-3 = -b^2
3= b^2
Take the square root
b=sqrt(3)
(x)^2 (y)^2
---------- + --------- = 1
4 3
I’m pretty sure the answer is C
Answer:
what's the question xjsbzbksns
Answer:
Teagan is dividing 6 by 11. If she continues the process, what will keep repeating in the quotient?
The sequence 05
Only the digit 5
The sequence 54
Only the digit 4
The sequence 54 is the final answer.
Step-by-step explanation:
Given:
A a fraction 6/11 which Teagan is dividing we have to find the repeating quotient.
Here the divisor is 11 and the dividend is 6.
Lets say that the quotient is "q" .
And we know that:
⇒ Dividend / divisor = quotient
Or
In mixed fraction.
⇒ Dividend / divisor = quotient + (remainder/ divisor)
Finding the values of "q".
⇒ 
⇒ 
Explanation:
- To divide
with 
we have to take a decimal in quotient which allows us to have a zero in each step in the quotient. - After putting zero the dividend will become
and then we can apply 
...
in the quotient and 
in the numerator. - In third step we will subtract with that will give us putting a zero with it it will be now
,and the closet multiple of is 
, 
with the quotient and and 
will continue to be divided. - The fraction is a rational numbers as the decimals occurring are repeating decimals in the quotient.
Our final answer from the option is : C
The sequence 54 will be repeating.
