Equation: y=-2x-4
slope: -2
y-int: -4
x-int: -2
We have sec =
1/cos
Then we also have
cos^2 = 1 – sin^2
Also we have cos = sqrt (1 – sin^2)
Substitute the derived cosine function to sec then we
have
Sec = 1/(sqrt(1-sin^2)
Firstly we need to find m<DNY
m<DNY=(60+90)÷2=75
N9w we can find m<KNY
m<KNY+m<DNY=180°(Because these are adjacent corners)
m<KNY+75°=180°
m<KNY=180°-75°
m<KNY=105°
Since the numbers are consecutive, they must be near each other in size, and therefore near one-third of 168. And since the lower number is -2 off the middle, and the upper number is +2 from the middle, the middle number must be exactly one-third of 168—otherwise the sum of the three could never be 168. Labelling the three consecutive numbers as x, y, and z:
x + y + z = 168
(y-2) + y + (y+2) = 168.
3y = 168
y = 56
therefore the smallest number (x) = 54.
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Related Questions (More Answers Below)
Answer:
Theres no solution ._.
Step-by-step explanation: Bc you have the 2 lines
