Answer:
<h2>: 7-⁴</h2>
Step-by-step explanation:
<h3>Exponential Form :</h3><h3>(a^m*a^n ) = (a^m+n )</h3>
<h3>7^-6 = 7^-2 * x </h3>
<h3>(only 7^-4 the term that can add to 7^-2 gives </h3><h3>= 7^-6 )</h3>
<h3>7^-6 = 7^-2 + 7^-4 </h3>
<h3> ( a^m*a^n) = ( a^m+n)</h3>
Answer:
B
Step-by-step explanation:
The zeros of the quadratic occur at x = 0 and x = 6
Thus the factors are x and x - 6
w represents width
4w represents length
d represents diagonal
w2 + (4w)2 = d2
w2 + 16w2 = d2
17w2 = d2
±w√17 = d
The diagonal is the width times √17.
V=L X W X H
1,296=6 x w x 24
1,296=144 x w
1296/144=w
9=width
Since m + n = 7 we know m = 7-n. So now we have 2n - 3(7-n) = 6. From this we get n = -3. So now we know m - 3 = 7 so m = 10. So now we have 3(-3) + 2(10) = ? and this comes out as 11
