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Dennis_Churaev [7]
2 years ago
13

Rewrite the following polynomial in standard form. 1 + 10x3 + x2

Mathematics
2 answers:
boyakko [2]2 years ago
4 0

Answer:

31 + x

Step-by-step explanation:

1) 1 + 10 × 3 + x

2) 1 + 30 + x

3) 31 + x

Mekhanik [1.2K]2 years ago
4 0

Answer:

X2+10x3+1....…...…............

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Write all the names of the quadrilateral shown.<br> ???
r-ruslan [8.4K]

Answer:

Rhombus

Step-by-step explanation:

3 0
3 years ago
Given JM=27, ml=16, jl=46, nk=15, KLM= 48, JkM=78, MJL=22, find each missing value.
Llana [10]

Answer:

KL = 27

JK = 16

MK = 30

NL = 23

m∠JKL = 132°

m∠KLJ = 22°

m∠KMJ = 54°

m∠KJL = 26°

Step-by-step explanation:

The given parameters of the quadrilateral JKLM are;

JM = 27, ML = 16, JL = 46, NK = 15, KLM = 48, JKM = 78, MJL = 22

Taking the sides as parallel, we have that quadrilateral JKLM is a parallelogram

Therefore;

KL = JM = 27

JK = ML = 16

m∠KLJ = m∠MJL = 22°

MN = NK = 15

MK = MN + NK = 15 + 15 = 30

NL = JL/2 = 46/2 = 23

m∠KJM = m∠KLM = 48°

m∠KJL = m∠KLM - m∠MJL = 48° - 22° = 26°

m∠KML = m∠JKM = 78°

m∠MKL = 180° - m∠KML - m∠KLM = 180° - 78° - 48° = 54°

m∠MKL = 54°

m∠JKL = m∠JKM + m∠MKL = 78° + 54° = 132°

m∠KMJ = m∠MKL = 54°

3 0
2 years ago
42.5% of 59.2 is what number?
Leokris [45]
The answer is 25.16
Hope this helps.
Please mark as Brainliest:)

4 0
3 years ago
What is the equation of a vertical line passing through the point (-4, 7)?
MrRa [10]

Answer:

x=-4

Step-by-step explanation:

Since we know that the equation will be x= we will just have to take the x value of the coordinate point and that would be the x so in this case the x is -4 so the equation would be x=-4

8 0
3 years ago
Point-slope of line's equation (-3,-7),(-8-11)
Nataly_w [17]
Steps:
1. Find the slope by using the slope formula
Y2-Y1
---------
X2-X1

-11 + 7
----------
-8 + 3
2.
-11 + 7= -4
-8 + 3= -5
3. Your slope is 4/5 (because you have to turn two negatives into a positive)
4. Now you do the point-slope formula
Y-Y1= m(x-x1)
Y +7=4/5 (x +3)
3 0
3 years ago
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