<h3>Given</h3>
4 hundreds flats; 5 tens rods; 2 ones cubes
<h3>Find</h3>
The number of hundreds flats in each of 2 equal piles
<h3>Solution</h3>
When 4 flats are divided into two equal groups, each group will have ...
... 2 flats
_____
You can imagine doing this the way a card dealer might: first put 1 flat in each of 2 piles, then do the same for the remaining 2 flats. Each pile will end up with 2 flats.
— — — — —
You will have a problem if you continue with the tens rods. There is an odd number of those, so one of them will have to be exchanged for 10 ones cubes.
Consider the function
, which has derivative
.
The linear approximation of
for some value
within a neighborhood of
is given by
Let
. Then
can be estimated to be
![\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B63.97%7D%5Capprox4-%5Cdfrac%7B0.03%7D%7B48%7D%3D3.999375)
Since
for
, it follows that
must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function
. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
Answer:
Answer is A.
Step-by-step explanation:
If you take the current cords of 'C' and add the cords it gives you: (4.5,-6.5). You end out with (3.5,-9,2). Hope this helps!
Answer:
f6h40
Step-by-step explanation:
Step 1 :
h23
Simplify ———
f3
Equation at the end of step 1 :
h23
((f9) • ———) • h17
f3
Step 2 :
Multiplying exponential expressions :
2.1 h23 multiplied by h17 = h(23 + 17) = h40
Final result :
f6h40
Answer:
its .23
Step-by-step explanation:
.23 is 23/100 becuase its in the hundreds of decimals. The percentage of 23/100 would just equal 23%
