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boyakko [2]
3 years ago
7

Which expression has the greatest value? ∣−25∣ ∣−16∣ ∣18∣ ∣−22∣

Mathematics
1 answer:
Alecsey [184]3 years ago
3 0

Answer: <em>|18| is the greatest value.</em>

Step-by-step explanation:

  • <u>|-25|, |-16| and |-22| are all negative numbers</u>.<em> </em>(Negative numbers are numbers that are <em>less</em> than zero.)
  • <u>|18| is a positive number</u>. (Positive numbers are whole numbers that is <em>larger</em> than zero. On a number line these numbers come<em> before zero and negative numbers</em>)
  • <em>|18| is a greater value because it is a positive number. </em>
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The answer is most likely C. Cubic meters.
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3 years ago
At a local sandwich shop the average customer spends $25 at dinner with a standard deviation of $2.30. In a simple random sample
oee [108]

Answer:

The probability that the mean receipt for dinner is between $24.50 and $25.50 is

P(24.50≤ x ≤ 25.50)= 0.8324

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given mean of Population(μ) = $25

Given standard deviation of the Population  (σ) = 2.30

Sample size 'n' = 40

Let 'X' be the random variable in normal distribution

Given X₁ = 24.50

Z_{1} =\frac{x-mean}{\frac{S.D}{\sqrt{n} } } = \frac{24.50-25}{\frac{2.30}{\sqrt{40} } } = -1.375

Given X₂ = 25.50

Z_{2} =\frac{x-mean}{\frac{S.D}{\sqrt{n} } } = \frac{25.50-25}{\frac{2.30}{\sqrt{40} } } = 1.3751

<u><em>Step(ii):-</em></u>

The probability that the mean receipt for dinner is between $24.50 and $25.50

P(x₁≤ x ≤ x₂) = P(Z₁≤ z ≤ Z₂) = A(Z₂) + A(z₁)

P(24.50≤ x ≤ 25.50) = P(-1.375≤ z ≤ 1.375) = A(1.375) + A(1.375)

P(24.50≤ x ≤ 25.50)= 2 A( 1.375)

                               = 2 × 0.4162 ( from normal table)

                              = 0.8324

<u><em>Final answe</em></u>r:-

The probability that the mean receipt for dinner is between $24.50 and $25.50 is 0.8324

4 0
4 years ago
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8(8u-5)

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Answer: hmm okay this is gonna be a hard one

Step-by-step explanation:

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Answer:

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