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soldier1979 [14.2K]
3 years ago
6

SOMEONE PLEASE HELP ILL GIVE BRAINIEST

Mathematics
1 answer:
Gala2k [10]3 years ago
3 0
The answer for this is, D
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3. Scout is conducting a research project on traffic patterns
ddd [48]

Answer:

7:45

Step-by-step explanation:

Since they both turn red at differnt times, you have to find a multiple to find the time they will be both on

Main St: 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98, 105

Elm St. 15, 30, 45, 60, 75, 90, 105

They will both turn on 105 minutes or 1 hour and 45 minutes from 6

6 + 1 hr 45 min = 7:45

8 0
3 years ago
Exercise Plus charges a yearly fee of $75 plus $10 a month. Gym and Swim charges a yearly fee of $50 plus $15 a month. When , if
Natasha2012 [34]

Answer:

5 months will be the same cost at each gym.

Step-by-step explanation:

As

  • Exercise Plus charges a yearly fee of $75 plus $10 a month.
  • Gym and Swim charges a yearly fee of $50 plus $15 a month.

Let x by the number of months

75+10x=50+15x

10x=15x-25

-5x=-25

\frac{-5x}{-5}=\frac{-25}{-5}

x=5

Therefore, 5 months will be the same cost at each gym.

4 0
2 years ago
When 3 times a number is subtracted from 10, the result is the sum of the number and 22
Arada [10]

Answer:

x = -6

Step-by-step explanation:

Let the number be x

<u>Condition:</u>

=> 10-3x = x+22

<u><em>Let's Solve it:</em></u>

=> -3x-x = 22-10

=> -2x = 12

<em>Dividing both sides by -2</em>

=> x = -6

6 0
3 years ago
Read 2 more answers
For what values of x will the result of 5x be greater than 1
SSSSS [86.1K]
Anything greater than (1/5) that is positive

Ex. (1/4), (1/3), (1/2), 1, 2, 3, 4, 5
6 0
2 years ago
The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.
zhuklara [117]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ h(t)=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{19}t+110~\hspace{10em}19~\frac{ft}{sec}

3 0
3 years ago
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