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Leona [35]
3 years ago
10

A square ____ has a symmetry with respect to a line containing a median of the square

Mathematics
2 answers:
Alexeev081 [22]3 years ago
8 0
The answer is yes true a square does have a symmetry with respect to a line containing a median of the square.
Korolek [52]3 years ago
3 0

The answer is yes it is True.

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Please Help!!! What is the end behavior of function h? h(x)=2(x-3)^2 As x approaches negative infinity, approaches negative infi
kramer

Answer:

Step-by-step explanation:

Function to be graphed is,

h(x) = 2(x - 3)²

Function 'h' is a quadratic function.

Since, the coefficient of the leading term (term with the highest power) is positive, parabola will open upwards.

Both the ends of the parabola will be upwards (towards positive infinity).

As x approaches to negative infinity, h(x) approaches to positive infinity.

As x approaches to positive infinity, h(x) approaches to positive infinity.

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3 years ago
4:X is equivalent to 24:12<br> X=???
Elena-2011 [213]

Answer:

X=2

Step-by-step explanation:

Ratios

4:x = 24:12

24:12 reduced is 2:1

Therefore we can see x must be half of 4.

So the answer is 2

Hope this helps! :)

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If amy sends 20emalis in 5minutes what ia the init rate
Maksim231197 [3]
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3 years ago
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PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!
jasenka [17]
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3 years ago
In a chemical plant, 24 holding tanks are used for final product storage. Four tanks are selected at random and without replacem
Damm [24]

Answer:

a) P(A) = 0,4607     or   P(A) = 46,07 %

b) P(B) = 0,7120   or 71,2 %

c) P(C) = 0,2055  or P(C) = 20,55 %

Step-by-step explanation:

We will use two concepts in solving this problem.

1.- The probability of an event (A) is for definition:

P(A) = Number of favorable events/ Total number of events FE/TE

2.- If A and B are complementary events ( the sum of them is equal to 1) then:

P(A) = 1 - P(B)

a) The total number of events is:

C ( 24,4) = 24! / 4! ( 24 - 4 )!    ⇒  C ( 24,4) = 24! / 4! * 20!

C ( 24,4) = 24*23*22*21*20! / 4! * 20!  

C ( 24,4) = 24*23*22*21/4*3*2

C ( 24,4) = 24*23*22*21/4*3*2    ⇒  C ( 24,4) =  10626

TE = 10626

Splitting the group of tanks in two 6 with h-v  and 24-6 (18) without h-v

we get that total number of favorable events is the product of:

FE = 6* C ( 18, 3)  = 6 * 18! / 3!*15!  =  18*17*16*15!/15!

FE =  4896

Then P(A) ( 1 tank in the sample contains h-v material is:

P(A) = 4896/10626

P(A) = 0,4607     or   P(A) = 46,07 %

b) P(B) will be the probability of at least 1 tank contains h-v

P(B) = 1 - P ( no one tank with h-v)

Again Total number of events is 10626

The total number of favorable events for the ocurrence of P is C (18,4)

FE = C (18,4) = 18! / 14!*4! = 18*17*16*15*14!/14!*4!

FE = 18*17*16*15/4*3*2  = 3060

Then P = 3060/10626

P = 0,2879

And the probability we are looking for is

P(B) = 1 - 0,2879

P(B) = 0,7120   or 71,2 %

c) We call P(C) the probability of finding exactly 1 tank with h-v and t-i

having 4 with t-i tanks is:

reasoning the same way but now having 4 with t-i (impurities) number of favorable events is:

FE = 6*4* C(14,2) = 24 * 14!/12!*2!

FE = 24* 14*13*12! / 12!*2

FE = 24*14*13/2    ⇒  FE = 2184

And again as the TE = 10626

P(C) = 2184/ 10626

P(C) = 0,2055  or P(C) = 20,55 %

5 0
3 years ago
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