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Leona [35]
3 years ago
10

A square ____ has a symmetry with respect to a line containing a median of the square

Mathematics
2 answers:
Alexeev081 [22]3 years ago
8 0
The answer is yes true a square does have a symmetry with respect to a line containing a median of the square.
Korolek [52]3 years ago
3 0

The answer is yes it is True.

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Can someone help me with this two step equation
hjlf
You have to distribute the 4 to the numbers in the parenthesese. So 4 times 3x which is 12x and 4 times 5 which is 20 so now you get 12x plus 20 equals 8. Now you have to subtract 20 from 8 which is -12 so now you have 12x=-12 now divide the 12 from x and 12 from -12 and so now you have x=-1
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Can you help with this math please?
Blababa [14]

Answer:

3 on the other side and 7 and 7 on the sides

Step-by-step explanation:

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19) Write 987% in decimal form
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The first two terms in an arithmetic progression are -2 and 5. The last term in the progression is the only number in the progre
Rudik [331]

Given:

The first two terms in an arithmetic progression are -2 and 5.

The last term in the progression is the only number in the progression that is greater than 200.

To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : a=-2

Common difference : d = 5 - (-2)

                                      = 5 + 2

                                      = 7

nth term of an A.P. is

a_n=a+(n-1)d

where, a is first term and d is common difference.

a_n=-2+(n-1)(7)

According to the equation, a_n>200.

-2+(n-1)(7)>200

(n-1)(7)>200+2

(n-1)(7)>202

Divide both sides by 7.

(n-1)>28.857

Add 1 on both sides.

n>29.857

So, least possible integer value is 30. It means, A.P. has 30 term.

Sum of n terms of an A.P. is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Substituting n=30, a=-2 and d=7, we get

S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]

S_{30}=15[-4+(29)7]

S_{30}=15[-4+203]

S_{30}=15(199)

S_{30}=2985

Therefore, the sum of all the terms in the progression is 2985.

6 0
3 years ago
From a collection of 52 store customers, 3 are to be chosen to receive a special gift. How many groups of 3 customers are possib
eimsori [14]

Answer:

132,600 possibilities

Step-by-step explanation:

The first one chosen can be 1 of 52

The 2nd one chosen is 1 out 51

And the 3rd chosen is 1 out 50

So...

52 x 51 x 50 = 132,600

3 0
3 years ago
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