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Sloan [31]
3 years ago
5

Simplify: V24 x V12 a. 6 b. 212 c. 28 d. 122

Mathematics
2 answers:
kumpel [21]3 years ago
7 0

Answer:

16.97

Step-by-step explanation:

The answer of this simplify if 16.97

Elanso [62]3 years ago
3 0

Answer:

16.97 or approx 17

Step-by-step explanation:

\sqrt{24} = \sqrt{4}\sqrt{6} = 2\sqrt{6}

\sqrt{12} = \sqrt{4}\sqrt{3} = 2\sqrt{3}

2\sqrt{6} · 2\sqrt{3} = 4\sqrt{18} = 4\sqrt{9}\sqrt{2} = 4·3\sqrt{2} = 12\sqrt{2} which is 16.97 or approx 17

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Step-by-step explanation:

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The band club needs $1328 for decorations for this year’s concert. So far, they have $43. Find the minimum amount each of the 30
Mariulka [41]

Answer:

$42.83

Step-by-step explanation:

1: Subtract the amount they have by the amount they need.

1328-43= $1,285.

2: Divide amount they need ($1,285) by the total staff members (30).                Hence the equation is 1285 ÷ 30

3: Whatever answer you get from that equation is the answer

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3 years ago
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A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

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Step-by-step explanation:

1,220,000 would be...

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