2 years ago

A^4 + 3a² - ( 5a - 3)(-7a) Please show work!!

1 answer:

7 0

$a^4+3a^2-(5a-3)(-7a)\ \ \ \ |\text{use distributive property}\\\\=a^4+3a^2-[(5a)(-7a)+(-3)(-7a)]\\\\=a^4+3a^2-(-35a^2+21a)\\\\=a^4+3a^2+35a^2-21a\\\\=a^4+38a^2-21a$

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Given 16 = −5 + z4solve for z

AysviL [449]

Hi,

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Now just divide both sides of equation by -4.

$z = \frac{21}{4}$

Simplify:

$z = 5 \frac{1}{4} \: \: \: \: \: \: \: \: \: \: \: \: \: fraction \: result$

Decimal form:

$z = 5.25 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: decimal \: result$

Hope this helps.
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