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vekshin1
3 years ago
10

Adding and subtracting polynomials (3x +4 – 2x) + (2x² – x+6)

Mathematics
2 answers:
Naya [18.7K]3 years ago
7 0
Like terms: 2x^2 +3x - 2x - x + 4 + 6.

Combine: 2x^2 + 4 + 6.

Add numbers: 2x^2 + 10. answer = 2x^2+10 :)
lapo4ka [179]3 years ago
5 0

Step-by-step explanation:

2x²+10

hope it helps u.........

stay home

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The following coordinates are found on a line on a graph: (4.3) and (8.
MA_775_DIABLO [31]

Answer:

both

Step-by-step explanation:

get a line graph

5 0
3 years ago
What is a8 for the geometric sequence 6,561;−2,187;729;−243;…6,561;−2,187;729;−243;….
VMariaS [17]
Consider a geometric sequence (u_n)

let u_1=a and the common ratio be r, then the sequence is constructed as follows:

u_1, u_2, u_3..... = a, ar, a r^{2}, a r^{3}, ...

we can observe that each term of the sequence is its previous term * r.


In the given sequence, to find the common ratio we divide 6,561 by −2,187 and get -3. This means that r= -\frac{1}{3}

Let the first term u_1=a=6,561, 

then the eighth term is  

u_8=a* r^{7}= 6,561 (- \frac{1}{3} )^{7}= -6,561*( \frac{1}{3} )^{7}= \frac{-6,561}{2187} =-3


Answer: -3
4 0
4 years ago
Chakara makes a rectangular tablecloth that is 3.5 meters long and 1.5 meters wide. What is the area of the tablecloth.
yarga [219]

Answer:

Area of the rectangular cloth = 5.25\,m^2

Step-by-step explanation:

Length of the cloth= 3.5\,m

Width of the cloth =1.5\,m

Area of the rectangular cloth is:

          Length\times Width

       Area =3.5\times 1.5\\\\=5.25\,m^2

The area of the rectangular cloth with the given dimensions is:

              5.25\,m^2

3 0
3 years ago
1:Under what condition will the line px+py+r=0 mat be a normal to the circke x²+y²+2gx+2fy+c=0
ahrayia [7]

Answer:

<h3>#1</h3>

The normal overlaps with the diameter, so it passes through the center.

<u>Let's find the center of the circle:</u>

  • x² + y² + 2gx + 2fy + c = 0
  • (x + g)² + (y + f)² = c + g² + f²

<u>The center is:</u>

  • (-g, -f)

<u>Since the line passes through (-g, -f) the equation of the line becomes:</u>

  • p(-g) + p(-f) + r = 0
  • r = p(g + f)

This is the required condition

<h3>#2</h3>

Rewrite equations and find centers and radius of both circles.

<u>Circle 1</u>

  • x² + y² + 2ax + c² = 0
  • (x + a)² + y² = a² - c²
  • The center is (-a, 0) and radius is √(a² - c²)

<u>Circle 2</u>

  • x² + y² + 2by + c² = 0
  • x² + (y + b)² = b² - c²
  • The center is (0, -b) and radius is √(b² - c²)

<u>The distance between two centers is same as sum of the radius of them:</u>

  • d = √(a² + b²)

<u>Sum of radiuses:</u>

  • √(a² - c²) + √(b² - c²)

<u>Since they are same we have:</u>

  • √(a² + b²) = √(a² - c²) + √(b² - c²)

<u>Square both sides:</u>

  • a² + b² = a² - c² + b² - c² + 2√(a² - c²)(b² - c²)
  • 2c² = 2√(a² - c²)(b² - c²)

<u>Square both sides:</u>

  • c⁴ = (a² - c²)(b² - c²)
  • c⁴ = a²b² - a²c² - b²c² + c⁴
  • a²c² + b²c² = a²b²

<u>Divide both sides by a²b²c²:</u>

  • 1/a² + 1/b² = 1/c²

Proved

6 0
3 years ago
Read 2 more answers
What values of x and y satisfy x + 2y = 6 and 2x + 3y = 4 simultaneously?
jeka94
First take x + 2y = 6 and isolate x:
x = 6 - 2y
Then substitute that for x in 2x + 3y = 4:
2(6 - 2y) + 3y = 4
12 - 4y + 3y = 4
12 - y = 4
-y = -8
y = 8
Substitute y = 8 into x + 2y = 6 and 2x + 3y = 4:
x + 2(8) = 6 --> x + 16 = 6 --> x = -10
2x + 3(8) = 4 --> 2x + 24 = 4 --> 2x = -20 --> x = -10
y = 8 and x = -10

4 0
3 years ago
Read 2 more answers
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