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yuradex [85]
3 years ago
14

Giving 25 points if you answer correctly. Please help thank you

Mathematics
1 answer:
Rasek [7]3 years ago
6 0
1.D 2.C 3.B 4.A hope this helps
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Larry is using an online calculator to calculate the outputs f(n) for different inputs n. The ordered pairs below show Larry's i
vredina [299]

Answer:

The answer is c. f(n)=4n+1

Step-by-step explanation:

In the function of the answers, n is the input and f(n) is the output. So the ordered pairs needs to be at the form (n,f(n))

Additionally, in the ordered pairs given in the question, the first term is the input and the second term is the output. For example in the ordered pair (1,5), 1 is the input and 5 is the output.

So, if we replace n by 1, f(n) needs to be 5. This condition is only satisfied on option c. That's is also prove for every ordered pair as:

For (1,5)

if n=1 then:

f(n)=(4*1)+1=5

For (2,9)

if n=2 then:

f(n)=(4*2)+1=9

For (3,13)

if n=3 then:

f(n)=(4*3)+1=13

For (4,17)

if n=4 then:

f(n)=(4*4)+1=17

Finally, the functions that best represents the rule that the calculator uses to display the outputs is f(n)=4n+1

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3 years ago
Just a question from a written Unit Test.
Rama09 [41]

Answer:

ok

Step-by-step explanation:

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3 years ago
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aniked [119]

Answer:  Sure!

Step-by-step explanation:

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Please please help I’m begging you to help
Ilia_Sergeevich [38]

Answer:

for every 1 vote cast on candidate d there is 4 votes cast on candidate c.

Step-by-step explanation:

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Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = ln(x), [1, 5]
matrenka [14]

Answer:

Yes, the function satisfies the hypothesis of the Mean Value Theorem on the interval [1,5]

Step-by-step explanation:

We are given that a function

f(x)=ln(x)

Interval [1,5]

The given function is defined on this interval.

Hypothesis of Mean Value Theorem:

(1) Function is continuous on interval [a,b]

(2)Function is defined on interval (a,b)

From the graph we can see that

The function is continuous on [1,5] and differentiable at(1,5).

Hence, the function satisfies the hypothesis of the Mean Value Theorem.

5 0
3 years ago
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