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2 years ago

11

Mrs. Ameldo's class has 5 students with blue eyes, 7 with brown eyes, 4 with hazel eyes, and 4 with green eyes. Two students are

selected at random. Find the probability of selecting a student with hazel eyes and then a student with blue eyes. Select one answer.
1/19

5/19

1/5

1 answer:

Vitek1552 [10]2 years ago

7 0

Answer:

5/19

Step-by-step explanation:

There's no explanation, it's just common sense ‍♀️

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To estimate the height of a house Katie stood a certain distance from the house and determined that the angle of elevation to th

Nata [24]

the height of the house is $408ft$ .

<u>Step-by-step explanation:</u>

Here we have , To estimate the height of a house Katie stood a certain distance from the house and determined that the angle of elevation to the top of the house was 32 degrees. Katie then moved 200 feet closer to the house along a level street and determined the angle of elevation was 42 degrees. We need to find What is the height of the house . Let's find out:

Let y is the unknown height of the house, and x is the unknown number of feet she is standing from the house.

Distance of house from point A( initial point ) = x ft

Distance of house from point B( when she traveled 200 ft towards street = x-200 ft

Now , According to question these scenarios are of right angle triangle as

At point A

⇒ $Tan32 =\frac{Perpendicular}{Base}= \frac{y}{x}$

⇒ $Tan32 = \frac{y}{x}$

⇒ $y=x(Tan32 )$ ..................(1)

Also , At point B

⇒ $Tan42 = \frac{y}{x-200}$

⇒ $y=(x-200)(Tan42)$ ..............(2)

Equating both equations:

⇒ $(x-200)(Tan42) = x(Tan32)$

⇒ $x(Tan42-Tan32)=Tan42(200)$

⇒ $x=\frac{Tan42(200)}{(Tan42-Tan32)}$

⇒ $x=653ft$

Putting $x=653ft$ in $y=x(Tan32 )$ we get:

⇒ $y=x(Tan32 )$

⇒ $y=653(Tan32 )$

⇒ $y=408ft$

Therefore , the height of the house is $408ft$ .

4 0

2 years ago

Which of the following sets of lengths can Sean use to make a right triangle?

Aleks [24]

Answer:

{8 cm, 15 cm, 17 cm}

Step-by-step explanation:

we know that

The length sides of a right triangle must satisfy the Pythagoras Theorem

so

$c^2=a^2+b^2$

where

c is the greater side (the hypotenuse)

a and b are the legs (perpendicular sides)

<u><em>Verify each case</em></u>

case 1) we have

{5 cm, 15 cm, 18 cm}

substitute in the formula

$18^2=5^2+15^2$

$324=250$ ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 2) we have

{6 cm, 12 cm, 16 cm}

substitute in the formula

$16^2=8^2+12^2$

$256=208$ ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 3) we have

{5 cm, 13 cm, 15 cm}

substitute in the formula

$15^2=5^2+13^2$

$225=194$ ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 4) we have

{8 cm, 15 cm, 17 cm}

substitute in the formula

$17^2=8^2+15^2$

$289=289$ ----> is true

therefore

Sean can make a right triangle with this set of lengths

6 0

2 years ago