This is a very poorly written question. im assuming the house wall is at least 130 ft since there is no information given about it.
each set of side lengths has three elements, the long side and the two short sides. we're asked to list all whole number possibilities so start anywhere, the two short sides being 1ft
(1 1 130). the long side has to be the difference of 132 and the length of both short sides.
the area is one of the short sides times the ling side, in the first case 1*130=130 sqft
continuing the list
(2 2 128) area=256
(3 3 126) area=378
(4 4 124) area=496
(5 5 122) area=610
the short sides increase by 1, the long side decreases by 2, the area gets bigger, but the difference between the areas are 4 less each time. dividing the first difference, 122, by 4 will give us a number to make a better guess from.
122÷4=30.5
so lets try
(30 30 72) area=2160
lets try 31 and see if that gives a smaller area
(31 31 70) area = 2170
(32 32 68) area =2176
(33 33 66) area = 2178
(34 34 64) area = 2176
so the area is decreasing now which means the maximum area is found when thw long side is 66 feet and the short sides are 33 feet.
as far as listing all possibilities, you see the pattern i started, i leave the rest to you
54 63 75 that’s in order 1.54 2.63 3.75
1) 1.403
2) 1.1
3) 1.078
4) 1.001
HOPE THIS HELPED :)
Answer:
$1170
Step-by-step explanation:
Let the sells for economy seats be =x
Let the sells for deluxe seats be=y
The inequalities that can be obtained are;
x≥1 --------------------at least 1 economy seats
y≥6 --------------------at least 6 deluxe seats
x+y=30-----------------maximum number of passengers allowed on each boat
Graph the inequalities
Use the graph tool to locate the point of maximum profit.The intersecting point for the three graphs
The point is (24,6)
Hence, x=24 and y=6
Profit for each
Economy seats 24×$40=$960
Deluxe seats 6×$35=$210
Maximum profit for one tour
$960+$210=$1170
