They need to admit 43 more cars to make at least $500
<u>Solution:</u>
Given, A drive in theater charges $3.50 per car,
The drive in already admitted 100 cars,
Then, money collected until now is $ 3.50 x 100 = $ 350
We have to solve an inequality to find the number of cars the drive in needs to admit to make atleast 500$
Now, let the number of cars need to be admitted be "n"
Then, inequality is:
collected amount + needed amount ≥ $ 500
$ 350 + $ 3.50 x n ≥ $ 500
350 + 3.5n ≥ 500
3.5n ≥ 500 – 350
On solving, we get
3.5n ≥ 150
n ≥ 42.857
As number of cars can’t be fractions, n = 43
Hence, they need to admit 43 more cars to make at least $500
Answer: Rational
Step-by-step explanation: To determine whether -3/4 is rational or irrational, remember that all fractions positive or negative are rational numbers.
Therefore, -3/4 is a rational number.
Answer:
(-5,1)
Step-by-step explanation:
Answer:
x = - 2√2
x = -2
Step-by-step explanation:
A . 5 + x² = 2 x² +13
5 + x² - 2 x² - 13 = 0
- x² -8 = 0
- x² = 8
x² = -8
x = - √8
x = - 2√2
B . 5 + x³ = 2 x³ + 13
5 + x³- 2 x³ - 13 = 0
- x³ -8 = 0
-x³ = 8
x³ = -8
x = - ∛8
x = -2
6, youd do 288/(4/3) which equals 216, then take the cube root of that which is 6