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alexandr1967 [171]
3 years ago
7

What’s the area and the circumference of a circle with diameter 8m?

Mathematics
1 answer:
MatroZZZ [7]3 years ago
8 0

Answer:

50.24

Step-by-step explanation:

8÷2 is the radius. 3.14×4^2=50.24 m^2

^= where the exponent is supposed to go

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Which table correctly represents these functions?
Wittaler [7]

Answer:

Graph C.

Step-by-step explanation:

C works the best when you plot the points on a graph, in reference to the functions provided...

*blue is the G(x) and red is the f(x) I believe*

Have a Great Day!

6 0
3 years ago
Is 6200 ft greater or less than 1 mile 900 ft
Sphinxa [80]
1 mile is equal to 5280 feet

Add 900 to it:

5280 + 900 = 6180

6180 is less than 6200, so 1 mile and 900 feet is less than 6200 feet.
7 0
3 years ago
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How many 1/3 inch cubes does it take to fill a box with width 2 2/3 inches, lengths 3 1/3 inches, and height 2 1/3 inches?
Nataly [62]

Answer:

560 cubes

Step-by-step explanation:

width: 8 cubes

length: 10 cubes

height: 7 cubes

volume: 8*10*7=560

divided l, w, and h by 1/3 to get them in cubes

7 0
3 years ago
Read 2 more answers
In this exercise, we estimate the rate at which the total personal income is rising in the Richmond-Petersburg, Virginia, metrop
lyudmila [28]

Answer:

The rate at which the total personal income was rising in the Richmond-Petersburg area in 1999 is $1.627 billion per year

Step-by-step explanation:

Let t be the number of years after 1999.

From the information given:

  1. In 1999, the population in this area was 961400, and the population was increasing at roughly 9200 people per year.
  2. The average annual income was 30593 dollars per capita, and this average was increasing at about 1400 dollars per year.

The population growth can be modeled with a linear equation. The initial population was P_0 is 961400 and it grows by 9200 people per year.

The population in time t can be written

P(t)=9200t+961400

The average annual income can be modeled with a linear equation. The initial average annual income was 30593 dollars per capita and it grows by  1400 dollars per year.

A(t)=1400t+30593

If we multiply both together gives the total personal income at time t.

T(t)=P(t)\cdot A(t)\\T(t)=(9200t+961400)\cdot (1400t+30593)

The rate at which the total personal income was rising in the Richmond-Petersburg area is the derivative T(t)'

We need to use the Product Rule that says

If f and g are both differentiable, then:

\frac{d}{dx}[f(x)g(x)]=f(x)\frac{d}{dx}[g(x)] +g(x)\frac{d}{dx}[f(x)]

Applying the Product Rule

\frac{d}{dt}T(t)=\frac{d}{dt} [(9200t+961400)\cdot (1400t+30593)]\\\\T(t)'=\frac{d}{dt}\left(9200t+961400\right)\left(1400t+30593\right)+\frac{d}{dt}\left(1400t+30593\right)\left(9200t+961400\right)\\\\T(t)'=9200\left(1400t+30593\right)+1400\left(9200t+961400\right)\\\\T(t)'=12880000t+281455600+12880000t+1345960000\\\\T(t)'=25760000t+1627415600

For 1999, t = 0.

The raising is

T(0)'=25760000(0)+1627415600\\T(0)'=1,627,415,600

The rate at which the total personal income was rising in the Richmond-Petersburg area in 1999 is $1.627 billion per year.

7 0
3 years ago
Solve for a.<br><br> a+(−1.2)=−5.5<br><br> Enter your answer in the box.<br><br> a =
Elden [556K]

Answer:

-4.3

Step-by-step explanation:

a+(-1.2)= -5.5

a-1.2=-5.5

add 1.2 to both sides

a-1.2+1.2= - 5.5+1.2

simplify

a= - 4.3

4 0
3 years ago
Read 2 more answers
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