2 years ago

Factorise: (Using Algebraic Identities) 64x^3-(4x-3y)^3

Mathematics

1 answer:

Naddika [18.5K]2 years ago

6 0

Answer:

9y(16x2−12xy+3y2)

Step-by-step explanation:

Factor 64x3−(4x−3y)3

144x2y−108xy2+27y3

=9y(16x2−12xy+3y2)

Answer:

9y(16x2−12xy+3y2)

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Solve the system of equations by the addition method.<br><br> 5x + 2y = 1<br> 2x - 2y = -8

dolphi86 [110]

Answer:

(-1, 3)

Step-by-step explanation:

5x + 2y = 1

2x - 2y = -8

7x = -7

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2(-1) - 2y = -8

-2 - 2y = -8

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3 years ago

Write three consecutive multiples of 13 in a general form.

S_A_V [24]

Answer:

answer given in step by step...

Step-by-step explanation:

13x+13(x+1)+13(x+2)=312

13x+13x+13+13x+26=312

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39x=312-39

39x=273

x=7

first number=13x=13*7=91

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2 years ago

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Lera25 [3.4K]

I think it’s $1.35 sorry if I’m not correct

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2 years ago

Read 2 more answers

Veronica gave 20% of her money to Bill. She used 50% of the remaining money to buy books.

Elina [12.6K]

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3 years ago

How do I Solve 4y + 3 = 2y + 14 ???

Aloiza [94]

$4y+3=2y+14$
subtract 2y from both sides to get the y figures on the same side.
$2y+3=14$
Then subract 3 from both sides to get the number values on the other side.
$2y=11$
Divide by 2 to get y alone.
$y=\frac{11}{2}$
$y= 5.5$

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3 years ago