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3 years ago

Anita brought chocolate and vanilla

Mathematics

1 answer:

Roman55 [17]3 years ago

4 0

Answer:

The percentage of the students picked a vanilla cupcake is 75%.

Step-by-step explanation:

Given that Anita brought chocolate and vanilla cupcakes to school for her birthday, and 64 students decided to take a cupcake, and 48 of them picked vanilla, to determine what percentage of the students picked a vanilla cupcake the following calculation must be performed:

64 = 100

48 = X

48 x 100/64 = X

4,800 / 64 = X

75 = X

Therefore, the percentage of the students picked a vanilla cupcake is 75%.

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Find the slope of the line whose equation is px - qy = r. q/p p/q -r/q

Zina [86]

Answer:

The slope is equal to

$m=\frac{p}{q}$

Step-by-step explanation:

we have

$px-qy=r$

Isolate the variable y

Subtract $px$ both sides

$px-qy-px=r-px$

$-qy=r-px$

Divide by $q$ both sides

$-y=(r-px)/q$

Multiply by $-1$ both sides

$y=(px-r)/q$

$y=\frac{p}{q}x-\frac{r}{q}$ ------> linear equation into slope-intercept form

the slope is equal to

$m=\frac{p}{q}$

The y-intercept is equal to

$b=-\frac{r}{q}$

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4 years ago

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seraphim [82]

Answer:

4.5

Step-by-step explanation:

I think it will work if you Divide 54 over 12 = 4.5

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3 years ago

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

wlad13 [49]

Answer:

$\frac{dy}{dx}=\frac{x(1-2lnx)}{x^{4}}$

Step-by-step explanation:

To solve the question we refresh our knowledge of the quotient rule.

For a function f(x) express as a ratio of another functions u(x) and v(x) i.e

$f(x)=\frac{u(x)}{v(x)}\\$ , the derivative is express as

$\frac{df(x)}{dx}=\frac{v(x)\frac{du(x)}{dx}-u(x)\frac{dv(x)}{dx}}{v(x)^{2} }$

from $y=lnx/x^{2}$

we assign u(x)=lnx and v(x)=x^2

and the derivatives

$\frac{du(x)}{dx}=\frac{1}{x}\\\frac{dv(x)}{dx}=2x\\$ .

Note the expression used in determining the derivative of the logarithm function.it was obtain from the general expression of logarithm derivative i.e $y=lnx\\\frac{dy}{dx}=\frac{1}{x}$