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skelet666 [1.2K]
3 years ago
14

A 12.0 L balloon at 84 °C is cooled until it

Chemistry
1 answer:
BARSIC [14]3 years ago
4 0
Use Charles’ Law: V1/T1 = V2/T2. Given a mass of gas held at a constant pressure, changes in the gas’s temperature and volume are directly proportional. Since the volume of the gas in the balloon decreased, we should expect that the temperature had also decreased.

Here, V1 = 12.0 L, T1 = 357.15 K, and V2 = 5.0 L. To solve for T2, we rearrange the equation and compute:

T2 = V2T1/V1 = (5.0 L)(357.15 K)/(12.0 L)
T2 = 148.8125 K - 273.15 = -124.34 °C

To two significant figures, the answer would be -120 °C.
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To do an experiment with the peptide H-A-P-P-Y you need to make two buffers. One where the peptide has a net negative charge (Bu
nata0808 [166]

Answer:

Buffer A: pH 5.25; 2.82 mol of acetate for every 1 mol of acetic acid

Buffer B: pH 9.25; 11.2 mol of bicarbonate for every 1 mol of carbonate

Explanation:

The pI of a protein is the pH at which it has a net charge of zero.

The protein has a positive charge below the pI and a negative charge above it.

Since pI = 7.25, let's make one buffer at pH = 5.25 and one at pH 9.25.

1. Preparation of pH 5.25 buffer

(a) Choose the conjugate pair

We should choose a buffer with pKₐ close to 5.25.

Acetic acid has pKₐ = 4.8, so let's make acetate buffer.

(b) Protocol for preparation

We can use the Henderson-Hasselbalch equation to get the acid/base ratio.

\begin{array}{rcl}\text{pH} & = & \text{pK}_{\text{a}} + \log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\5.25& = & 4.8 +\log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\0.45& = & \log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\2.82 & = &\dfrac{[\text{A}^{-}]}{\text{[HA]}}\\\\\end{array}\\\text{The base/acid ratio must be $\mathbf{2.82:1}$}

To make the buffer, mix the solutions to get a ratio of 2.82 mol of acetate for every 1 mol of acetic acid.

2. Preparation of pH 9.25 buffer

(a) Choose the conjugate pair

We should choose a buffer with pKₐ close to 9.25.

Bicarbonate has pKₐ = 10.3, so let's make a pH 9.25 bicarbonate buffer.

(b) Protocol for preparation

\begin{array}{rcl}\text{pH} & = & \text{pK}_{\text{a}} + \log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\9.25& = & 10.3 +\log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\-1.05& = & \log \left(\dfrac{[\text{A}^{-}]}{\text{[HA]}}\right )\\\\0.08913& = &\dfrac{[\text{A}^{-}]}{\text{[HA]}}\\\\\dfrac{1}{11.2}& = &\dfrac{[\text{A}^{-}]}{\text{[HA]}}\\\\\end{array}\\\text{The acid/base ratio must be $\mathbf{11.2:1}$}

To make the buffer, mix the solutions to get a ratio of 11.2 mol of bicarbonate for every 1 mol of carbonate.

3 0
3 years ago
Which of the following elements can form double covalent bonds?
labwork [276]

Answer:

double bond

Explanation:

Sometimes two covalent bonds are formed between two atoms by each atom sharing two electrons, for a total of four shared electrons. For example, in the formation of the oxygen molecule, each atom of oxygen forms two bonds to the other oxygen atom, producing the molecule O2. Similarly, in carbon dioxide (CO2), two double bonds are formed between the carbon and each of the two oxygen atoms

8 0
3 years ago
You have a bag of chips at a constant pressure of 1 Atm with a volume of .5 L and a temperature of 10C. The bag is left under th
Lera25 [3.4K]

Answer:

0.54 L

Explanation:

Given that,

Initial volume, V₁ = 0.5 L

Initial temperature, T₁ = 10°C = 283 K

Final temperature, T₂ = 35 C = 308 K

We need to find the final volume. The relation between the volume and temperature is given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{0.5\times 308 }{283}\\\\V_2=0.54\ L

So, the new volume is 0.54 L.

4 0
3 years ago
Who developed the first scientific atomic theory?
Annette [7]

Answer:

John Dalton

Explanation:

John Dalton (1766-1844) is the scientist credited for proposing the atomic theory. This theory explains several concepts that are relevant in the observable world.

7 0
2 years ago
A small gas cylinder of Helium can be used to fill many more balloons than would fit inside it. Explain how this works, in your
Fudgin [204]
<h2>Gas Molecules Move in Random Motion </h2>

Explanation:

  • According to the property of an ideal gas the volume occupied by the gas molecules themselves is negligible as compared to the volume occupied by the gas
  • The molecules of ideal gas obey Newton's laws of motion thus they move in random motion
  • According to the above statements we can conclude that Helium gas can fill many more balloons as compared to fit the baloons inside the cylinder because the particles of gas is free to move in random motion and can occupy more volume
6 0
3 years ago
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