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azamat
3 years ago
8

Solutions of sodium sulfate and silver nitrate are mixed together.

Chemistry
1 answer:
leonid [27]3 years ago
4 0

Precipitate is silver sulfate and the net ionic equation is

2Ag⁺(aq) + SO₄²⁻(aq) → Ag₂SO₄(s)

<u>Explanation:</u>

The given reaction is the reaction of sodium sulfate with silver nitrate and as the reaction goes we will get the precipitate of Silver sulfate and the balanced reaction is given as,

Na₂SO₄ + 2 AgNO₃→ Ag₂SO₄↓ +  2 NaNO₃

Here silver sulfate is obtained as a precipitate.

Net ionic equation is the equation in which the ions involved in the reaction only taken into account that is ions forming precipitate, whereas the other ions are considered as spectator ions, ions do not involved in the reaction.

Here the net ionic equation is:

2Ag⁺(aq) + SO₄²⁻(aq) → Ag₂SO₄(s)

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What reaction conditions most effectively conver a cabocxylic acid to a methly ester?
VLD [36.1K]

Answer:

Esterification reaction

Explanation:

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7 0
3 years ago
A laboratory technician combined sodium hydroxide with excess iron(II) nitrate. A reaction took place according to this chemical
Whitepunk [10]

 The initial  mass  of sodium hydroxide  is  3.3 g (answer C)

 <u><em>calculation</em></u>

Step 1 : find the  moles of iron (ii) hydroxide (  Fe(OH)₂

moles =  mass÷  molar mass

from periodic table the  molar mass of Fe(OH)₂  = 56 + [16 +1]2  = 90 g/mol

moles  is therefore = 3.70 g÷ 90 g/mol = 0.041 moles

Step 2:  use the mole ratio to  calculate the moles of  sodium hydroxide (NaOH)

   from given equation  NaOH : Fe(OH)₂    is 2 :1

therefore the moles of NaOH = 0.041 x 2 = 0.082 moles

Step 3: find  mass of NaOH

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from the periodic table the  molar mass of NaOH = 23 +16 +1  = 40 g/mol

mass  = 0.082  moles x 40 g/mol = 3.3 g ( answer C)


8 0
3 years ago
What happens to the chemical identity of a substance during a physical change?
klio [65]
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gavmur [86]
  The  condensed  structural  formula  of the  product  of the  reaction of 2,7-dimethyl-4-octene  with hydrogen   and metal  catalyst.

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Equation  is  as follows

 CH3 CH(CH3) CH2  C=C CH2 CH(CH3)  CH3  +  H2
→

CH3 CH(CH3)CH2 CH2 CH2 CH2 CH(CH3) CH3

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6 0
4 years ago
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