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aniked [119]
3 years ago
10

What problems must be overcome before fusion can be used to produce energy? A. synthesizing deuterium and tritium and containing

the plasma reactants
B. achieving high temperatures and containing the plasma reactants
C. achieving high temperatures and synthesizing deuterium and tritium
Chemistry
2 answers:
harina [27]3 years ago
6 0

There are two main problems to overcome before fusion can produce energy:1) it must be able to achieve high enough temperatures to start the reaction.

2) Must contain plasma.

TEA [102]3 years ago
3 0

Answer: Option (B) is the correct answer.

Explanation:

Plasma is the hot gas which is ionized and has equal number of both positive ions and negatively charged electrons.

To carry out nuclear fusion reaction it is necessary to provide high temperature. Though there is high temperature so, gases present in the reaction will also reach at high temperature.

Therefore, these gases will convert into plasma.

Thus, we can conclude that achieving high temperatures and containing the plasma reactants  are the problems that must be overcome before fusion can be used to produce energy.


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Dumbledore decides to gives a surprise demonstration. He starts with a hydrate of Na2CO3 which has a mass of 4.31 g before heati
vovikov84 [41]

Answer:

Na₂CO₃.2H₂O

Explanation:

For the hydrated compound, let us denote is by Na₂CO₃.xH₂O

The unknown is the value of x which is the amount of water of crystallisation.

Given values:

Starting mass of hydrate i.e Na₂CO₃.xH₂O = 4.31g

Mass after heating (Na₂CO₃) = 3.22g

Mass of the water of crystallisation = (4.31-3.22)g = 1.09g

To determine the integer x, we find the number of moles of the anhydrous Na₂CO₃ and that of the water of crystallisation:

        Number of moles  = \frac{mass }{molar mass }

Molar mass of Na₂CO₃ =[(23x2) + 12 + (16x3)]  = 106gmol⁻¹

Molar mass of H₂O = [(1x2) + (16)] = 18gmol⁻¹

Number of moles of Na₂CO₃ = \frac{3.22}{106} = 0.03mole

Number of moles of H₂O =  \frac{1.09}{18} = 0.06mole

From the obtained number of moles:

                          Na₂CO₃                               H₂O

                           0.03                                    0.06

Simplest

Ratio                  0.03/0.03                         0.03/0.06

                                 1                                      2

Therefore, x = 2    

7 0
3 years ago
a brick measures 25cm by 12cm by 13cm. What is the volume of the brick in cm cubed? how many milliliters of water would this bri
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The volume is 3900cm^3 and the bricks density is 3900 ml
5 0
3 years ago
If 9.85 grams of copper metal react with 31.0 grams of silver nitrate, how many grams of copper nitrate can be formed and how ma
Veseljchak [2.6K]

Answer:-

29.07 gram of Cu(NO3)2 will be formed.

4.756 grams of AgNO3 will be left over when the reaction is complete.

Explanation:-

Atomic weight of Cu = 63.546 g mol -1

Molecular weight of AgNO3 = 107.87 x 1 + 14 x 1 + 16 x 3

= 169.87 g mol-1

Number of moles of Copper = 9.85 gram / (63.546 g mol-1)

= 0.155 mol

Number of moles of AgNO3 = 31 gram / ( 169.87 g mol-1)

= 0.183 mol

The balanced chemical equation for this reaction is

Cu + AgNO3 --> Cu(NO3)2 + Ag

According to the equation,

1 mole of Cu reacts with 1 mole of AgNO3.

∴0.155 mol of Cu react with 0.155 mol of AgNO3.

Number of moles of AgNO3 left over = 0.183-0.155=0.028 mol

Number of grams of AgNO3 left over = 0.028 mol x 169.87 grams mol-1

= 4.756 gram

Molecular weight of Cu(NO3)2 = 63.546 x 1 + (14 x 1 +16 x 3 ) x 2

=187.546 gram

Now from the balanced chemical equation,

1 Cu gives 1 Cu(NO3)2

∴ 63.546 g of Cu gives 187.546 gram of Cu(NO3)2

9.85 grams pf Cu gives 187.546 x 9.85 / 64.546 gram of Cu(NO3)2

= 29.07 gram of Cu(NO3)2

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Answer:

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What is the function of a hypothesis in the scientific inquiry process?
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It's a question that scientists can test.
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