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Verdich [7]
3 years ago
7

How can the equation below be rewritten to solve for c

Mathematics
1 answer:
kvasek [131]3 years ago
3 0
1. a=b+cx
2. a-b=cx subtract b
3. a-b/x=c divide by x to get c by itself
Answer: a-b/x=c
You might be interested in
The sum of 2 numbers is 48and there difference is 24 what are the numbers
andreyandreev [35.5K]
The two numbers would be 36 and 12
36 + 12 = 48
36 - 12 = 48
8 0
3 years ago
If 3/4 +1/6 =p then the value of p is what?
laila [671]

Answer: 11/12

Step-by-step explanation:

Addition of fractions

#1 Change to the same denominator

- LCM (Least common multiple) of 4 and 6 is 12

- 9/12+2/12

#2 Add the numerator as usual

 9/12+2/12

=(9+2)/12

=11/12

-------------------------------------------------

p=3/4+1/6

p=11/12

3 0
3 years ago
There are 135 people in a sport centre. 77 people use the gym. 62 people use the swimming pool. 65 people use the track. 27 peop
umka21 [38]

Answer:

The correct answer is \frac{2}{9}.

Step-by-step explanation:

There are 135 people in a sport centre.

Let the experiment be to pick a person from the sport centre who only uses exactly one of the facilities.

Total number of possible outcomes = 135

For the gym:

77 people use the gym.

27 people use the gym and the pool.

31 people use the gym and the track.

4 people use all three facilities.

Total number of people using only the gym are 77 - ( 27 + 31 + 4) = 15

For the swimming pool:

62 people use the swimming pool.

27 people use the gym and the pool.

23 people use the pool and the track.

4 people use all three facilities.

Total number of people using only the swimming pool are 62 - ( 27 + 23 + 4) = 8

For the tracks:

65 people use the track.

23 people use the pool and the track.

31 people use the gym and the track.

4 people use all three facilities.

Total number of people using only the tracks are 65 - ( 23 + 31 + 4) = 7

A person is selected at random.

Favorable outcomes = 7 + 8 + 15 = 30

Probability that the person uses exactly one of the facilities = \frac{Favorable}{Total} = \frac{30}{135}  = \frac{2}{9}.

5 0
3 years ago
Pls help me to find the answer e,f,g,h no. only
Nikitich [7]

1. Change both numbers to common base.

2. Use quotient rule a^x \div a^y = a^{x-y}

e)

You can write 9 as 3², then both numbers have the same base.

9^x = (3^2)^x = 3^{2x}, where x is the exponent

I cannot really see the exponents because picture is bad quality.

9^x \div 3^y =

= (3^2)^x \div 3^y =

=3^{2x} \div 3^y =

= 3^{2x-y}

You want to replace x and y with actual numbers, but as I said the picture is too bad.

f)

Convert to base 4, then quotient rule.

g)

Use the quotient rule, you already have same base.

h)

Convert to base \frac{2}{3}, then quotient rule.

6 0
2 years ago
Can someone please help me?
Zigmanuir [339]
12 is the answer to this quest
5 0
3 years ago
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