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3 years ago

NEED HELP ASAP

Mathematics

1 answer:

KonstantinChe [14]3 years ago

3 0

Answer:

All in the explanation.

Step-by-step explanation:

Since we will only be renting the car for one day it will only be a $50 dollar base fee. If we drive 192 miles and just rent it for one day the equation modeled will be $0.18(192) + 50 = 34.56 + 50 = $84.56 total.

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What is the answer of 10 to the power of -4<br><br> [tex] 10^-4

malfutka [58]

Remember
$x^{-m}= \frac{1}{x^m}$

so

$10^{-4}= \frac{1}{10^4}= \frac{1}{10000}=0.0001$

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3 years ago

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
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$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

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$d^2=4+1$
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$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

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3 years ago

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loris [4]

Answer:

Idk if this is right but I think it's The transformed shaped shifted 7 units to the right so add 7 to x and it shifted 6 units down so subtract 6 from y.

The answer is (x,y) = (x+7) (y-6)

Hope this helps!!!?

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lara [203]

Answer:

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Step-by-step explanation:

I can give you the answer but you have to be patient like 30 min

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stiv31 [10]

Answer:

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Step-by-step explanation:

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