Number of tickets: T.
Number of customers: c
Initially the number of tickets is T0=150, when the group hasn't sold any tickets (c=0). Then the graph must begin with c=0 and T=150. Point=(0,150). Possible options: Graph above to the right and graph below to the left.
They sell the tickets in pack of three tickets per customer c, then each time they sell a pack of three tickets to a customer, the number of tickets is reduced by 3 (-3c). Then the number of tickets, T, the group has left after selling tickets to c customers is:
T=150-3c→T=-3c+150
For T=0→-3c+150=0→150=3c→150/3=c→c=50. The graph must finish with c=50, T=0. Final point=(c,T)=(50,0)
Answer:
The correct graph is above to the right, beginning on vertical axis with T=150 and finishing on horizontal axis with c=50.
The correct equation is T=-3c+150
It is understood without being written that the slope of this line is 1. If we rewrite the point-slope form of the line it would be y-8=1(x-4) where 1 is the slope. We move the -8 over by addition to get y = 1x-4+8, or, simplified, y=x+4, the first choice in your answers.
Given:
Radius = 14 ft
θ = 45°
To find:
Area of the shaded sector
Solution:
Area of the sector formula:
ft²
The area of the shaded sector of a circle is 24.5π ft².
Answer:
-3(4+2n) multiply -3 by 4 and 2n
-12-6n
