Segment in the direction from A to C
Initial Point: A=(9,5)=(xa,ya)→xi=xa=9, yi=ya=5
Final point: C=(-7,1)=(xc,yc)→xf=xc=-7, yf=yc=1
B=(xb,yb)=?
Proportion: r=AB/BC=3:1=3/1→r=3
xb=(xi+r*xf)/(1+r)
Replacing xi=xa=9, xf=xc=-7 and r=3
xb=[9+3*(-7)]/(1+3)
xb=(9-21)/4
xb=(-12)/4
xb=-3
yb=(yi+r*yf)/(1+r)
Replacing yi=ya=5, yf=yc=1 and r=3
yb=[5+3*(1)]/(1+3)
yb=(5+3)/4
yb=8/4
yb=2
B=(xb,yb)→B=(-3,2)
Answer: B=(-3,2)
Option C, y = 1/2 x -2 is the correct answer
Answer:
-2
Step-by-step explanation:
First, you need to find the equation.
f(x) = -3x + b
Now we need to find the y-intercept.
f(x) = -3x + b
f(-9) = -3(1) + b
-9 = -3 + b
-6 = b
f(x) = -3x - 6
The zero of f means that f(x) = 0
f(0) = -3x - 6
f(6) = -3x
x = -2
No idea hope you figure it out tho !!
maybe 3?
Hell naw, nobody is about to do that for you
