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AlexFokin [52]
3 years ago
6

The sum of Joy's age and her brother's age is 24. Joy's brother's age is 3 years older than twice joy's age. What is the differe

nce between their ages?
Mathematics
1 answer:
enyata [817]3 years ago
3 0
Let Joy be x years old

<span>Joy's brother's age is 3 years older than twice joy's age.
</span>Joy's Brother = 2x + 3

<span>The sum of Joy's age and her brother's age is 24.
x + 2x + 3 = 24
3x + 3 = 24
3x = 24 - 3
3x = 21
x = 21 </span>÷ 3 
x = 7

Joy:
x = 7

Brother:
2x + 3 = 2(7) + 3 = 17

Difference in their age = 17 - 7 = 10 years

They are 10 years apart.
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e \:  = \frac{dq}{dp}  \times  \frac{p}{q}

When q = 150, we have;

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e \:  =  \frac{1}{13} \times  \frac{50}{150}  = 0.0256

The point elasticity of demand, <em>E </em>= <u>0.0256</u>

  • The <u>demand is inelastic</u> (less than 1) when the quantity demanded is 150 units

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0.0256 \:  =  \frac{1}{13} \times  \frac{p}{140}  =

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brainly.com/question/19141990

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