Make x the subject
2x = -3y + 1
5x = -2y -3
now times the answers to get the lcd
(2x = -3y + 1) x 5
10x = -15y + 5
(5x = -2y -3) 2
10x = -4y -6
now that they are equal to the same number:
-15y + 5 = -4y -6
-15y + 4y = -6 -5
-11y = -11
y = 1
now to find x we substitute y
2x = -3y + 1
2x = -3(1) + 1
2x = -3 + 1
2x = -2
x = -1
The easiest way to find the expansion of the expression given would e to distribute. To distribute, you have to multiply each of the terms in the parentheses by 9. The expansion of the expression would be 9x + 18.
9 (x + 2)
9 · x = 9x
9 · 2 = 18
9x + 18
Hope this helps. Good luck! :)
Answer:
The correct answer is 3x
Step-by-step explanation:
Add 2x and x
~Hoped this helped~
~Brainiliest, please?~
<span>There are several possible events that lead to the eighth mouse tested being the second mouse poisoned. There must be only a single mouse poisoned before the eighth is tested, but this first poisoning could occur with the first, second, third, fourth, fifth, sixth, or seventh mouse. Thus there are seven events that describe the scenario we are concerned with. With each event, we want two particular mice to become diseased (1/6 chance) and the remaining six mice to remain undiseased (5/6 chance). Thus, for each of the seven events, the probability of this event occurring among all events is (1/6)^2(5/6)^6. Since there are seven of these events which are mutually exclusive, we sum the probabilities: our desired probability is 7(1/6)^2(5/6)^6 = (7*5^6)/(6^8).</span>
Answer:
In this equation n = 15
Step-by-step explanation:
In order to find this, we first must make each term a base 3. Since 9 is 3 squared, we can change it easily to base 3.
3^5 * 9^5 = 3^n
3^5 * (3^2)^5 = 3^n
3^5 * 3^10 = 3^n
3^15 = 3^n
Now that we have both in simple term of 3 raised to a power, we can eliminate the 3's and see that 15 = n
