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choli [55]
3 years ago
10

Please answer ASAP I’ll mark brainliest

Mathematics
1 answer:
Leni [432]3 years ago
6 0

Answer:

Step-by-step explanation:

Range=highest number - lowest number

let 4 be smallest number so

x=55

let 4 be largest number

x=4-55

=-51

hope this helps u):

You might be interested in
Add five thousand, three hundred and twelve thousandths to the product of one and thirty six hundredths and 15
MAVERICK [17]
First find the product of 1.36 and 15

1.36×15=20.4

5,300.012+20.4= 5,320.412

hope this is what you are looking for
7 0
3 years ago
Paul is building a bridge for a school project and wants to make a right triangle out of three popsicle sticks that measure 8 cm
STatiana [176]

Answer:

No he can't

Step-by-step explanation:

8² = 64

10² = 100

8² + 10² = 164

18² = 324

For a right triangle A²+B²=C²

4 0
2 years ago
Hi can anyone help me with this ..​
aleksley [76]

Answer:

n = π/6, π/4, 3π/4, 5π/6

Step-by-step explanation:

sin(3n) − sin n = cos(2n)

Use double and triple angle formulas:

(3 sin n − 4 sin³ n) − sin n = 1 − 2 sin² n

2 sin n − 4 sin³ n = 1 − 2 sin² n

4 sin³ n − 2 sin² n − 2 sin n + 1 = 0

Factor by grouping:

2 sin² n (2 sin n − 1) − (2 sin n − 1) = 0

(2 sin² n − 1) (2 sin n − 1) = 0

Solve:

2 sin² n − 1 = 0

2 sin² n = 1

sin² n = 1/2

sin n = √2/2

n = π/4, 3π/4

2 sin n − 1 = 0

2 sin n = 1

sin n = 1/2

n = π/6, 5π/6

4 0
3 years ago
Please i need help with 4th grade math please write the answer and shiw the solution hownto solve the problem step by step.thank
julia-pushkina [17]

Answer:

110

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which of the following is an extraneous solution of (45-3x)^1/2=x-9?
Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0
4 years ago
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