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3 years ago

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find the common ratio of the following geometric sequence. 2.512, 11.304, 50.868, 228.906, 1,030.077, ...

1 answer:

zimovet [89]3 years ago

8 0

In mathematics, a geometric progression<span>, also known as a </span>geometric sequence<span>, is a </span>sequence<span> of numbers where each term after the first is found by multiplying the previous one by a common ratio. We determine the ratio as follows:

r = 11.304 / 2.512 = 4.5
r = </span>50.868 / <span>11.304 = 4.5
r = </span>228.906 / 50.868 = 4.5

Therefore, the common ration is 4.5.

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During a field trip, 60 students are put into equal-sized groups. Describe two ways to interpret 60 ÷ 5 in this problem *

sergeinik [125]

Answer:

$x=12 groups$

This will give 5 Students each in 12 different equally sized groups

$x'=5groups$

This also shows that students can grouped in equal groups of 12 in 5 places

Step-by-step explanation:

From the question we are told that

60 children in equal sized groups

Generally interpreting $60\div 5$ can be mathematically represented as

a)

$x=\frac{60}{5}$

$x=12 groups$

This will give 5 Students each in 12 different equally sized groups

b)

$x'=\frac{60}{12}$

$x'=5groups$

This also shows that students can grouped in equal groups of 12 in 5 places

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3 years ago

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worty [1.4K]

Answer:

Approximately : 135

Step-by-step explanation:

60sec x 3 = 180sec

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Nezavi [6.7K]

Answer:

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Step-by-step explanation:

I think the ans is 45.6

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2 years ago

Which statement about the simplified binomial expansion of (a + b)", where n is a positive integer, is true?

Alja [10]

Answer:

$(a+b)^n ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + ..... +{n \choose n}a^{(0)}b^{(n)}$

Step-by-step explanation:

The Given question is INCOMPLETE as the statements are not provided.

Now, let us try and solve the given expression here:

The given expression is: $(a +b)^n, n > 0$

Now, the BINOMIAL EXPANSION is the expansion which describes the algebraic expansion of powers of a binomial.

Here, $(a+b)^n = \sum_{k=0}^{n}{n \choose k}a^{(n-k)}b^{(k)}$

or, on simplification, the terms of the expansion are:

$(a+b)^n ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + ..... +{n \choose n}a^{(0)}b^{(n)}$

The above statement holds for each n > 0

Hence, the complete expansion for the given expression is given as above.

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