Complete Question
A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:
a)F minimum
b) F maximum
c) Frequency resolution
Answer:
a) 
b) 
c) 
Step-by-step explanation:
From the question we are told that:
Time 
Frequency
Segments 
Generally the equation for Frequency Range is mathematically given by


Therefore
a) 
b) 
c)
Generally the equation for Frequency Resolution is mathematically given by

Where
N=The Total dat points
N=Sampling Frequency *Time


Therefore


(1.6666667)x+(.5)=0
1.6666667x=-.5
1.6666667x/1.666667=-.5/1.6666667
x= -.5/1.6666667
x=.3
Answer:
17 units
Step-by-step explanation:
split the shape into several little ones that you have formulas for :)
Answer:
Step-by-step explanation:
p+1 +8 = 8p+16
p+9 = 8p+16
9-16 = 8p-p
-7=7p
-7/7 =p
-1=p
2x^2 is not a like term in the given expression (since the given like terms contain only 1 power of x)