Answer:
0.000003721m
Scientific Notation: 3.72*10^-6
Step-by-step explanation:
1nm is 1*10^-6nm
Based on that we find the answer above.
Answer:
$31.80
Step-by-step explanation:
The ball will cost 100% of its price plus 6% of its price for a total of 106%.
To use percentages as a factor and multiply, they must be divide by 100, making the multiplication factor version of 106% 1.06.
Multiply the cost of the ball by your multiplication factor:
30 x 1.06 = 31.8
Money is written to two decimal places, making your answer $31.80
Answer:
1.)
≈ 3.652
2.) I would say something about how the A in front of cos in the equation would change to 90, rather than stay 75 (in the equation for the step by step), but it would be easier to just use the Pythagorean theorem.
Step-by-step explanation:
I think we may have the same class so hopefully this helps:
1.)
--> law of cosines formula.
--> plugged in numbers; when you draw the triangle, the included angle would be A, and the opposite side would be a. B and b, and C and c are opposite each other. In this case, a is the hypotenuse.
--> in between steps.
--> more simplifying.
--> answer
2.) This one is just an explanation: The 75 in the equation is the given angle, which is a. If this changes, it would just change in the equation too. And obviously, if it's 90 degrees, you can just use Pythagorean theorem a^2+b^2=c^2.
Good luck! :)
11*2 = 22 (calculating the diameter)
Using πD for the area:
π * 22 = 22π
Getting 3/4 of the area because the dog can not move past the corners of the garage;
22π * 3/4 = 16.5π
Getting the answer in feet^2:
16.5 * 3.14 = 51.84 feet^2
Hope this helps! :)
Answer:
$4
Step-by-step explanation:
The two purchases can be written in terms of the cost of an adult ticket (a) and the cost of a student ticket (s):
7a +16s = 120 . . . . . . . . price for the first purchase
13a +9s = 140 . . . . . . . . price for the second purchase
Using Cramer's rule, the value of s can be found as ...
s = (120·13 -140·7)/(16·13 -9·7) = 580/145 = 4
The cost of a student ticket is $4.
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<em>Comment on Cramer's Rule</em>
Cramer's rule is particularly useful for systems that don't have "nice" numbers that would make substitution or elimination easy methods to use. If you locate the numbers in the equation, you can see the X-patterns that are used to compute the numerator and denominator differences.
The value of a is (16·140 -9·120)/(same denominator) = 1160/145 = 8. I wanted to show you these numbers so you could see the numerator X-pattern for the first variable.
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Of course, graphical methods can be quick and easy, too.