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3 years ago

The ratio is 5:3 there is 20 girls and 16 boys if three girls are absent what would the ratio be

Mathematics

2 answers:

Leokris [45]3 years ago

7 0

hcxtfitifigukktzkydkuduodkudkuf

zepelin [54]3 years ago

7 0

You could divide is and that will get you your answer

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Pyramid A is a right square pyramid with a height of 100 m and a square base with a perimeter of 356 m. Pyramid B has a square b

Tomtit [17]

Answer:

The volume of pyramid B is 3.5 times greater than the volume of pyramid A

Step-by-step explanation:

The area of squared based a pyramid is given by:

$Area = \frac{1}{3}*s*s*h$

Where 's' the length of the side of the base and 'h' is the height.

For pyramid A:

h= 100 m

s= 356/4 = 89 m

$Area_A = \frac{1}{3}*89*89*100\\Area_A=264,033.33\ m^3$

For pyramid B:

h= 215 m

s= 456/4 = 114 m

$Area_B = \frac{1}{3}*114*114*215\\Area_B=931,380\ m^3$

Pyramid B has a greater volume and the ratio between volumes is:

$\frac{Area_B}{Area_A} =\frac{931,380}{264,033.33}\\\frac{Area_B}{Area_A} =3.5$

3 0

3 years ago

What is the following simplified product? Assume x≥0. 2√8x^3(3√10x^4-x√5x^2)

natta225 [31]

i think the answer is A.

5 0

3 years ago

Find a and b such that gcd(a, b) = 14, a > 2000, b > 2000, and the only prime divisors of a and b are 2 and 7.

choli [55]

Answer:

$a = 2^\alpha.14 \ ,\alpha\geq 8\\b = 7^\delta.14 \ , \delta\geq 3$

Step-by-step explanation:

As 2 and 7 are the only prime divisors of both $a$ and $b$ we know that both can be written as:

$a = 2^\alpha . 7^\beta \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\$

Where $\mathbb{N}_{0}$ is the set of all natural numbers adding the zero (careful because this part is important as I'll explain next).

We also know that 14 divides both numbers and that is actually the greatest common divisor between them. So we can rewrite a and b as follows:

$a = 2^\alpha . 7^\beta.14 \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta.14 \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\$

Why do I write them like this? Because this way is easier to observe that if $\alpha$ and $\gamma$ were both greater than zero, then 28 would divide both hence 14 wouldn't be their g.c.d.. Likewise, if $\beta$ and $\delta$ were both greater than zero, then 98 would divide both and once again, 14 wouldn't be their g.c.d.

So either of them has to be equal to zero. And then we have that

$a = 2^\alpha.14 \\b = 7^\delta.14$

All we have left to do is find the possible values for $\alpha$ and $\delta$ so that $a>2000 \ , b>2000$ and that only happens if $\alpha\geq 8$ and $\delta\geq 3$