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2 years ago

Hi! So, I've got a question. My Math problem is a 2 part problem. Let me just write it out real quick.

Mathematics

1 answer:

Igoryamba2 years ago

4 0

Okay!

This problem is a systems of equations - graphically, your answer will be where all the lines in the problem/system intersect.

You are given two rates at the beginning of the problem:

Keith's rate: 6 pages a day

Tameka's rate: 5 pages a day, 15 page headstart.

When you are given a rate, that is automatically a line! That's what makes these systems of equations really neat.

Try taking Keith and Tameka's rates individually and come up with an equation for the both of them, and then put the two on a graph.

(hint: substitute <em>x</em> for pages)

Good luck!

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Whichwhich would you measure using inches? A. length of a pen B. height of a flagpole C. length of a cross-country race course D

Taya2010 [7]

Answer:

The length of a pen.

Step-by-step explanation:

A length of a pen is around three inches and is reasonable but all of the others are way too big and can be measured in feet or miles.

3 0

3 years ago

What is an equation of the line that passes through the point (−8,−1) and is parallel to the line x-4y=4x

avanturin [10]

Answer:

y = -3/4x - 7

Step-by-step explanation:

Parallel lines have the same slope.

Solve for y in the equation to find the slope.

x - 4y = 4x

-4y = -x + 4x

-4y = 3x

y = 3/-4 x = -3/4x So the slope is -3/4 which is the coefficient of the

x term

Substitute the slope(m) = -3/4 and point (-8, -1) into y = mx + b to solve for "b"

y = mx + b

-1 = -3/4(-8) + b

-1 = 6 + b

-1 - 6 = b

-7 = b

The equation of the new line: y = mx + b

y = -3/4x - 7

5 0

2 years ago

Solve for the variable b. 5a(b - c ) = d

anyanavicka [17]

The answer probably would be this 5ab-5ac=d

5 0

3 years ago

Integrate this two questions

tankabanditka [31]

Simplify the integrands by polynomial division.

$\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)$

$\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)$

Now computing the integrals is trivial.

$\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}$

where we use the power rule,

$\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)$

and a substitution to integrate the last term,

$\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)$

$\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}$

using the same approach as above.

5 0

2 years ago

Y=4x-9 <br> complete the missing value in the solution to the equation <br> (3,__)

kozerog [31]

So we need to plug in our values so now y=4(3)-9 so 4*3 is 12 now we have y=12-9 Subtract 12 and nine to get 3 so y equals 3.
The answer is (3, 3). Hope this helped please look at others answers and check other resources as well

5 0

3 years ago

Read 2 more answers