There are three consecutive integers, such that six times the first, minus two times the second, equals the third integer plus f
ive. What is the first integer described? Will give Brainliest!!!!!!!!!!!!
1 answer:
Answer:
3
Step-by-step explanation:
Given that:
Integers : x, x + 1, x + 2
6x - 2(x + 1) = (x+2) + 5
6x - 2x - 2 = x + 2 + 5
4x - 2 = x + 7
4x - x = 7 + 2
3x = 9
x = 9/3
x = 3
First integer = x = 3
2nd integer = x + 1 = 3+1 = 4
3rd Integer = x + 1 + 1 = 3 + 2 = 5
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i hope my ans is correct if not i apologise.