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Tju [1.3M]
2 years ago
6

There are three consecutive integers, such that six times the first, minus two times the second, equals the third integer plus f

ive. What is the first integer described? Will give Brainliest!!!!!!!!!!!!
Mathematics
1 answer:
frozen [14]2 years ago
7 0

Answer:

3

Step-by-step explanation:

Given that:

Integers : x, x + 1, x + 2

6x - 2(x + 1) = (x+2) + 5

6x - 2x - 2 = x + 2 + 5

4x - 2 = x + 7

4x - x = 7 + 2

3x = 9

x = 9/3

x = 3

First integer = x = 3

2nd integer = x + 1 = 3+1 = 4

3rd Integer = x + 1 + 1 = 3 + 2 = 5

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