<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
Hi there!
I'm unsure if '11/4 pounds' meant '1/4', however, if it did, the answer is 6 pies in total.
Here's how I worked it out:
9 - 1.5 = 7.5 ( 1 )
7.5 - 1.5 = 6 ( 2 )
6 - 1.5 = 4.5 ( 3 )
4.5 - 1.5 = 3 ( 4 )
3 - 1.5 = 1.5 ( 5 )
1.5 - 1.5 = 0 ( 6 )
<em>Hope I helped! (:</em>
Answer:
12y+9
Step-by-step explanation:
Alright, lets get started.
The side of square base is given 0.25 in. (say a)
The height of pyramid is given 1.2 in. (say h)
The formula for surface area A is given below:
A=a^2+2a √(a^2/4+ h^2 )
Putting the value of a and h .

Putting the value of a and h

Hence the area of pyramid is 0.6625 square inches. : Hope it will help :)
88 - 14 = 72
72/15 = 4.8 ≈ 5
Class interval = 5